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anonymous
 one year ago
Find dy/dx by implicit differentiation x^2=(x+y)/(xy)
anonymous
 one year ago
Find dy/dx by implicit differentiation x^2=(x+y)/(xy)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just started learning this too :) lurking to see what I can learn.. there are some great helpers on tonight. hold tight

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1take them on side first

asnaseer
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to use the quotient rule?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x,y)=x^2\frac{x+y}{xy}=0\\y'=\frac{ f'_x(x,y) }{ f'_y(x,y) }\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1\[2x\frac{ (x+y) }{ (xy )}=0\]\[2x\frac{ (xy)(1+\frac{ dy }{ dx })(x+y)(1\frac{ dy }{ dx }) }{ (xy)^{2} }=0\]\[2x[(x+x \frac{ dy }{ dx }yy \frac{ dy }{ dx }) (xx \frac{ dy }{ dx }+yy \frac{ dy }{ dx }]/(xy)^{2}=0\]\[2x\frac{ x+x \frac{ dy }{ dx }yy \frac{ dy }{ dx } x+x \frac{ dy }{ dx }y+y \frac{ dy }{ dx }}{ (xy )^{2}}=0\]\[2x\frac{ 2x \frac{ dy }{ dx }2y }{ (xy)^{2}}=0\]\[2x=\frac{( 2x \frac{ dy }{ dx }2y) }{ (xy)^{2} }\]\[2x(xy)^{^{2}}=2x \frac{ dy }{ dx }2y\]\[2x(xy)^{2}+2y=2x \frac{ dy }{ dx }\]\[\frac{ 2x(xy)^{2}+2y }{ 2x }=\frac{ dy }{ dx }\]\[(xy)^{2}+\frac{ y }{ x }=\frac{ dy }{ dx }\]
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