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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just tell me how to solve it (formula, etc.)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0is it given that PS is perpendicular to QR ?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1is PS pependicular to Qr ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nope nothing else is given

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1if there is no condition more ,this is not solvable ! but if ps perpendicular to qr first \[qs^2+9^2=15^2\\qs=12\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pythagoras theorem? right?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.1then use sin60 to find pr and use cos 60 to find sr \[\sin60=\frac{ \sqrt{3} }{ 2 }=\frac{ 12 }{ pr}\\cos 60 =\frac{ 1 }{ 2 }=\frac{ sr }{ pr}\] from the first find pr put in second , and find sr

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll can you check the answer?
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