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Just tell me how to solve it (formula, etc.)
is it given that PS is perpendicular to QR ?

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Other answers:

is PS pependicular to Qr ?
nope nothing else is given
if there is no condition more ,this is not solvable ! but if ps perpendicular to qr first \[qs^2+9^2=15^2\\qs=12\]
pythagoras theorem? right?
then use sin60 to find pr and use cos 60 to find sr \[\sin60=\frac{ \sqrt{3} }{ 2 }=\frac{ 12 }{ pr}\\cos 60 =\frac{ 1 }{ 2 }=\frac{ sr }{ pr}\] from the first find pr put in second , and find sr
pythagoras ,yes
Parameter is 44.79?
@UsukiDoll can you check the answer?
I was afk :/
Its ok

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