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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    Just tell me how to solve it (formula, etc.)

  3. ganeshie8
    • one year ago
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    is it given that PS is perpendicular to QR ?

  4. amoodarya
    • one year ago
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    is PS pependicular to Qr ?

  5. anonymous
    • one year ago
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    nope nothing else is given

  6. amoodarya
    • one year ago
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    if there is no condition more ,this is not solvable ! but if ps perpendicular to qr first \[qs^2+9^2=15^2\\qs=12\]

  7. anonymous
    • one year ago
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    pythagoras theorem? right?

  8. amoodarya
    • one year ago
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    then use sin60 to find pr and use cos 60 to find sr \[\sin60=\frac{ \sqrt{3} }{ 2 }=\frac{ 12 }{ pr}\\cos 60 =\frac{ 1 }{ 2 }=\frac{ sr }{ pr}\] from the first find pr put in second , and find sr

  9. amoodarya
    • one year ago
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    pythagoras ,yes

  10. anonymous
    • one year ago
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    Parameter is 44.79?

  11. anonymous
    • one year ago
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    @UsukiDoll can you check the answer?

  12. UsukiDoll
    • one year ago
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    I was afk :/

  13. anonymous
    • one year ago
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    Its ok

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spraguer (Moderator)
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