## TrojanPoem one year ago Chemistry question:

1. TrojanPoem

In the reaction: [N_{2} + 3H_{2} \rightarrow 2NH_{3}\] if the formation rate of [NH_{3}\] = 3 ml/min , therefore the consumption rate of [H_{2}\] = ...... ml / min

2. TrojanPoem

$N_{2} + 3H_{2} \rightarrow 2NH_{3}$

3. TrojanPoem

[N= 14, H = 1]

4. TrojanPoem

1.059

5. TrojanPoem

The book choices are 1.5 , 4.5 , 3 , 5 so which ?

6. TrojanPoem

Oh fine ( I am used to do it with the arrows

7. TrojanPoem

18/17 = 1.06 approx

8. TrojanPoem

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9. TrojanPoem

Now, what to do ? Question : Can we do it with rate of change (maths) Derivative ?

10. dan815

wait ill rewrite this, i know a better simpler way

11. TrojanPoem

Hey ?

12. TrojanPoem

You slept ?

13. dan815

|dw:1435496147891:dw|

14. dan815

|dw:1435496565413:dw|

15. dan815

tthats it

16. vera_ewing

@dan815 I didn't know that you're good at chemistry! :)

17. dan815

im not lol

18. vera_ewing

Hahaha well good work on this question :)

19. dan815

how come its none of the answer choices though

20. dan815

the choices seem kind of crazy to begin with though... how can u consume so much of H2 for such little Nh3 "The book choices are 1.5 , 4.5 , 3 , 5 so which ?"

21. TrojanPoem

This are the rates of formation

22. TrojanPoem

Any ideas dan ?

23. taramgrant0543664

Would it just simply be the rate of formation of NH3 is 3mL/min and 2moles are made of NH3 but 3mols of H2 are consumed so 3/2=1.5x3=4.5? I don't know if you be able to do that but it's one of the options for an answer

24. TrojanPoem

@taramgrant0543664 , It's (4.5 ml/min).You are right.

25. dan815

interesting xD i have been edumacated

26. dan815

my bad, i didnt mean to mislead you, I was thinking we were dealing with mass quantities, when ml in fact referred to milli liters which meant milli cm^3 so it was always a volume to begin with, sorry!

27. TrojanPoem

No problem dan. Thanks for helping.