Chemistry question:

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In the reaction: [N_{2} + 3H_{2} \rightarrow 2NH_{3}\] if the formation rate of [NH_{3}\] = 3 ml/min , therefore the consumption rate of [H_{2}\] = ...... ml / min
\[N_{2} + 3H_{2} \rightarrow 2NH_{3}\]
[N= 14, H = 1]

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Other answers:

1.059
The book choices are 1.5 , 4.5 , 3 , 5 so which ?
Oh fine ( I am used to do it with the arrows
18/17 = 1.06 approx
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Now, what to do ? Question : Can we do it with rate of change (maths) Derivative ?
wait ill rewrite this, i know a better simpler way
Hey ?
You slept ?
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tthats it
@dan815 I didn't know that you're good at chemistry! :)
im not lol
Hahaha well good work on this question :)
how come its none of the answer choices though
the choices seem kind of crazy to begin with though... how can u consume so much of H2 for such little Nh3 "The book choices are 1.5 , 4.5 , 3 , 5 so which ?"
This are the rates of formation
Any ideas dan ?
Would it just simply be the rate of formation of NH3 is 3mL/min and 2moles are made of NH3 but 3mols of H2 are consumed so 3/2=1.5x3=4.5? I don't know if you be able to do that but it's one of the options for an answer
@taramgrant0543664 , It's (4.5 ml/min).You are right.
interesting xD i have been edumacated
my bad, i didnt mean to mislead you, I was thinking we were dealing with mass quantities, when ml in fact referred to milli liters which meant milli cm^3 so it was always a volume to begin with, sorry!
No problem dan. Thanks for helping.

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