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anonymous
 one year ago
If h''(t)=1, h'(2)=3 and h(4)=5, find h(6)
anonymous
 one year ago
If h''(t)=1, h'(2)=3 and h(4)=5, find h(6)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know what the antiderivative of 1 is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, but you have to add C as a constant of integration because both y = x and y = x + 2 have 1 as a derivative. So when you take the antiderivative of h"(t) = 1, you get h'(t) = x + C Then you use the fact that h'(2) = 3 to solve for C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so.. 2+C=3 then, solve for C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right. so the first derivative is h'(t) = x + 1. now take the antiderivative of that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0h(t) = 1/2x^2+x+C Use h(4)=5 to find C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right. h(t) = ½t² + t  7. All that's left is to find h(6)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much :)
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