chrisGA
  • chrisGA
Simplify square root of 2 multiplied by the cube root of 2.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
what r ur options
chrisGA
  • chrisGA
2 to the power of 1 over 6 2 to the power of 2 over 3 2 to the power of 5 over 6 2 to the power of 7 over 6
anonymous
  • anonymous
@DarkMoonZ

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anonymous
  • anonymous
Yes?
anonymous
  • anonymous
help him
anonymous
  • anonymous
Sorry but I am a "Time Traveling Donkey" I am bad at math :/ I am great at history tho :D
TheSmartOne
  • TheSmartOne
Is your question: \(\sf\Large \sqrt[2]{\sqrt[3]{2}}\)
anonymous
  • anonymous
the best person to help
anonymous
  • anonymous
i thought to be adding the powers @TheSmartOne but then it doesnot match his options
TheSmartOne
  • TheSmartOne
I saw someone answer a similar question yesterday :)
chrisGA
  • chrisGA
|dw:1435506182407:dw|
anonymous
  • anonymous
ohh
TheSmartOne
  • TheSmartOne
and btw, \(\bf\huge~~~~\color{#ff0000}{W}\color{#ff2000}{e}\color{#ff4000}{l}\color{#ff5f00}{c}\color{#ff7f00}{o}\color{#ffaa00}{m}\color{#ffd400}{e}~\color{#bfff00}{t}\color{#80ff00}{o}~\color{#00ff00}{O}\color{#00ff40}{p}\color{#00ff80}{e}\color{#00ffbf}{n}\color{#00ffff}{S}\color{#00aaff}{t}\color{#0055ff}{u}\color{#0000ff}{d}\color{#2300ff}{y}\color{#4600ff}{!}\color{#6800ff}{!}\color{#8b00ff}{!}\\\bf ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~Made~by~TheSmartOne\) Hey there!!! @chrisGA Since you are new here, read this legendary tutorial for new OpenStudiers!! http://openstudy.com/study#/updates/543de42fe4b0b3c6e146b5e8
chrisGA
  • chrisGA
ok
TheSmartOne
  • TheSmartOne
ok, do you know this property: \(\sf\Large \sqrt[x]{y}= y^{\frac{1}{x}}\)
chrisGA
  • chrisGA
no
TheSmartOne
  • TheSmartOne
well, we will need to use that for this question.
LynFran
  • LynFran
ok your question can be written as\[2^{\frac{ 1 }{ 2 }}*2^{\frac{ 1 }{ 3 }}\]
LynFran
  • LynFran
now when your multiplying sumthing with the same component we add the base...can u do that?
TheSmartOne
  • TheSmartOne
you also need to use the property: \(\sf\Large a^b \times a^c = a^{b+c}\) Do you know this property?

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