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TrojanPoem

  • one year ago

After passing quantity of electricity in H2SO4 solution , 2 moles of H2 gas was formed, and when passing the same quantity of electricity in HCl Solution ..... moles of the same gas is formed. Explain your asnwer.

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  1. aaronq
    • one year ago
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    Have you tried writing equations for this?

  2. aaronq
    • one year ago
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    Remember that electricity are just electrons, you're using these electrons to reduce \(H^+\) to \(H_2\).

  3. TrojanPoem
    • one year ago
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    @aaronq , At first I was thinking of using Friday law : \[\frac{ Mas(x) }{ equivalentMass(x) } = \frac{ Mass(Y) }{ EM(Y) }\] But I don't have either equivalent masses.

  4. TrojanPoem
    • one year ago
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    I think equivalent masses are both for (H) so Mass(X) = Mass(Y) Moles of X = Moles of Y = 2 ?

  5. aaronq
    • one year ago
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    you dont actually need any formulas, to answer the question to you only need to think conceptually and see where the electrons are going. You used the same amount of electricity (electrons) in both cases, right? ---- yes, 2 moles, the same amount of moles.

  6. TrojanPoem
    • one year ago
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    Thanks. I never feel convinced of my answer until I assure it with formula. But was using the formula right ?

  7. TrojanPoem
    • one year ago
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    And what was confusing my is that H2SO4 <- 2 H so in mole = 2 * NA HCl-> 1 H so in mole = 1 * NA

  8. aaronq
    • one year ago
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    yeah, but unless HCl was limited then you would get as much H2 as you could reduce. in other words: 2 HCl + e -> 2 H2 + Cl^-

  9. aaronq
    • one year ago
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    i guess using the formula works out in this case, although it's really not needed

  10. TrojanPoem
    • one year ago
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    @aaronq , Thanks.

  11. aaronq
    • one year ago
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    no problems

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