help pweaseee D: Andy has two similar conical hats, Hat A and Hat B. The diameter of Hat A is 18 inches, and the diameter of Hat B is 9 inches. What is the ratio of the volume of Hat A to the volume of Hat B? 2:1 16:1 4:1 8:1

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help pweaseee D: Andy has two similar conical hats, Hat A and Hat B. The diameter of Hat A is 18 inches, and the diameter of Hat B is 9 inches. What is the ratio of the volume of Hat A to the volume of Hat B? 2:1 16:1 4:1 8:1

Mathematics
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Volume of a cone is \[\pi*r ^{2}*h/3\]
And diameter is just 2r, so for hat A r=9 in and hat B r=4.5 in
im following :)

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Set up an equation that has volume on both sides like so: \[\pi*r _{A}^{2}*h/3=\pi*r _{B}^{2}*h/3\]
As you can see, the pi and h/3 will cancel out once you divide both sides by them. Then you are left with r^2 on each side for the respective cones.
And you can take it from there =P
ok one sec :D
so it would be.. \[9^2 = 4.5^2\] which will simplify to \[4:1\] ? :D
smarty pants :3
X'D
thanks guys :))
Yeah you got it!
Every ratio type problem can be handled this way
alright thank you so much :))
it wasnt 4:1 :( .. oh well thanks though :)
XDD
:O oha! how so?
Hmm is it not? Let me plug everything in myself
no idea @annas and @nuttyliaczar no worries its fine , unless u want to check it :3
I just checked and still got 4:1
i'll asj my teacher, thanks anyways :)
annas cookies *_*
Volume for A = pi*r^2*h/3 = 254.469*h/3 Volume for B = pi*r^2*h/3 = 63.617*h/3
Dividing them gives 4/1 so... I'm not sure why that was wrong
its ok i'll talk to my teacher :) thanks though i really appreciate ur help guys :)

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