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anonymous
 one year ago
The function H(t) = 16t2 + vt + s shows the height H(t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second.
Part A: The projectile was launched from a height of 96 feet with an initial velocity of 80 feet per second. Create an equation to find the time taken by the projectile to fall on the ground.
Part B: What is the maximum height that the projectile will reach? Show your work.
Part C: Another object moves in the air along the path of g(t) = 31 + 32.2t where g(t) is the height, in fe
anonymous
 one year ago
The function H(t) = 16t2 + vt + s shows the height H(t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A: The projectile was launched from a height of 96 feet with an initial velocity of 80 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. Part B: What is the maximum height that the projectile will reach? Show your work. Part C: Another object moves in the air along the path of g(t) = 31 + 32.2t where g(t) is the height, in fe

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points) Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know?

perl
 one year ago
Best ResponseYou've already chosen the best response.1Which part would you like help with?

perl
 one year ago
Best ResponseYou've already chosen the best response.1Ok we can start with part a)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe once i get started i MIGHT be able to do it thanks so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0H(t) = 16t^2 + 80t + 96

perl
 one year ago
Best ResponseYou've already chosen the best response.1We are given that \( H(t) = 16t^2 + vt + s\) shows the height H(t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A) The projectile was launched from a height of 96 feet with an initial velocity of 80 feet per second. That means s = 96 and v = 80

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so my equation becomes : H(t) = 16t^2 + 80t + 96

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so thats part A right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now part b i have to find the maximum

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the axis of symmetry is 2.5?

perl
 one year ago
Best ResponseYou've already chosen the best response.1the maximum or minimum of a parabola occurs at \(\large t= \frac { b}{2a} \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so I got a maximum of 196

perl
 one year ago
Best ResponseYou've already chosen the best response.1how plug in that time t = 2.5 to find the maximum height

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so now part c... now i really dont know where to start

perl
 one year ago
Best ResponseYou've already chosen the best response.1Part C) the directions are not complete . Can you check

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes hang on one sec please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part C: Part C: Another object moves in the air along the path of g(t) = 31 + 32.2t where g(t) is the height, in feet, of the object from the ground at time t seconds.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values]

perl
 one year ago
Best ResponseYou've already chosen the best response.1We want to find when \( H(t) = g(t) \) which would ordinarily mean solve the equation \( 16t^2 + 80t + 96= 31 + 32.2t \) but instead of solving for t , here they ask us to make tables for the left side and right side separately, and estimate when they are closest

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so I would solve each equation both H(t) and g(t) by plugging in the numbers 15?

perl
 one year ago
Best ResponseYou've already chosen the best response.1we can find y values for both H(t) and g(t) and then estimate where they are closest

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so we would do that by plugging in 0 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so g(t) = 31 + 32.2t , g(t) = 31 + 32.2(0) , g(t) = 31 + 0 , g(t) = 31 H(t) = 16t^2 + 80t + 96 , H(t) = 16(0)^2 + 80(0) + 96 , H(t) = 0 + 0 + 96 , H(t) = 96

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the yintercept for H(t) = 16t^2 + 80t + 96 is 96 and the yintercept for g(t) = 31 + 32.2t is 31

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help me with part d @perl

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0equation 1: (4,160) equation 2: (4, 159.8) what does it represent in the context of the problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they almost intersect when x = 4 what is the meaning in the context of the problem?

perl
 one year ago
Best ResponseYou've already chosen the best response.1at time t = 4 seconds the paths are closest to each other

perl
 one year ago
Best ResponseYou've already chosen the best response.1the projectiles are closest

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks! what about part d?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when the projectiles re going down because H(t) = 16t^2 +80t +96 is decreasing just as the other equation is increasing?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@perl is that correct??

perl
 one year ago
Best ResponseYou've already chosen the best response.1when the projectile h(t) is coming down , yes

perl
 one year ago
Best ResponseYou've already chosen the best response.1the projectile g(t) is going up the whole time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks so much !!!!!!
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