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anonymous
 one year ago
Find the standard form of the equation of the parabola with a focus at (8, 0) and a directrix at x = 8.
anonymous
 one year ago
Find the standard form of the equation of the parabola with a focus at (8, 0) and a directrix at x = 8.

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Hero
 one year ago
Best ResponseYou've already chosen the best response.1Okay, go ahead and solve it using the formula I gave you previously. This time, the point for the directrix will be (8,y).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got \[y=x8\sqrt{2}\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.1You should show the complete work you did on it. From what I observe, your final answer doesn't seem to have the right form.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im skipping the first step cause It takes so long to write \[\large x^2 + 64 +y^2 = x^2  64 +x^2  y^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Hero \[\large 64 = x^2  y^2  64\] I feel like this is a formula of some sort...

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Skipping steps doesn't sound like such a good idea.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I didn't skip any but the first where you plug in the values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0next i did this: \[\large y^2 = x^2  128\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then took the square root of both sides

Hero
 one year ago
Best ResponseYou've already chosen the best response.1That still doesn't look right.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1You must have made another mistake.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1BTW, \(y^2 + y^2 = 2y^2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0left that out by accident

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large 64 = 2y^2 +x^2 64\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does that look right?

Hero
 one year ago
Best ResponseYou've already chosen the best response.1I wrote out the steps by hand myself. There's a reason why I wanted you to post each step you did just like last time. If you skip steps, you end up confusing yourself. Also, if you never got to the point where you end up using difference of squares, then you may have made yet another mistake.

Hero
 one year ago
Best ResponseYou've already chosen the best response.1I recommend starting over but posting each step this time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large (x+8)^2 +y^2 = (x8)^2 + (xy)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large then: x^2 +64 +y^2 = x^2 64 +x^2  y^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you see any problems yet? @hero

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Yes, I do actually. Double check your work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large x^2 + 64 +y^2 = x^2 +64 +x^2 +y^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can't believe I didn't see that earlier

Hero
 one year ago
Best ResponseYou've already chosen the best response.1What didn't you see earlier?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in the last parentheses in the formula I put an x instead of a y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And when I simplify that down it comes out to \[\large y=\sqrt{32x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0unless I did that extremely wrong which I felt like I did

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Yes, because you should have isolated x instead of y.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok. So what you had was correct

Hero
 one year ago
Best ResponseYou've already chosen the best response.1The parabola is horizontal instead of vertical.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have some more if you don't mind :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Different type of question

Hero
 one year ago
Best ResponseYou've already chosen the best response.1Actually, I'm about to log off soon. Others should be available to help.
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