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anonymous

  • one year ago

How many moles of sulfuric acid are needed to produce 57.8 milliliters of water? Water has the density of 0.987 g/mL. Show all steps of your calculation as well as the final answer. NaOH + H2SO4 → Na2SO4 + H2O @aaronq

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  1. aaronq
    • one year ago
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    First find the moles of water present in 57.8 mL To do this find the mass using the density, convert the mass to moles. Next balance the equation given

  2. anonymous
    • one year ago
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    Can you walk me through the question because I don't understand Stoichiometry

  3. anonymous
    • one year ago
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    @aaronq

  4. aaronq
    • one year ago
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    First find the mass knowing that: \(\sf density =\dfrac{mass}{Volume}\) then balance the equation, when you do that we can work through the rest.

  5. Photon336
    • one year ago
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    1The first thing you need to do is to consider how many moles of H20 are in that volume, that's why they gave you the density, so you can multiply mL x (g/mL) and you get the number of grams of water. 2Now you have the number of grams of water but you need the number of moles so you have to multiply the number of grams times the molar mass of h20 (1mol/18gH20) and from this you get the number of moles of H20. 3But the question asked for the number of moles of H2S04 so for this part I think you multiply the number of moles of water by the molar ratio which is h20x(h2so4/h20) it's a 1:1 ratio and you get your answer.

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