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mckenzieandjesus

  • one year ago

did i do this right? What is the standard form of the equation of the circle in the graph? (x - 3)2 + (y + 1)2 = 1 (x + 3)2 + (y - 1)2 = 2 (x + 3)2 + (y - 1)2 = 1 (x - 3)2 + (y + 1)2 = 2

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  1. mckenzieandjesus
    • one year ago
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  2. mckenzieandjesus
    • one year ago
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    i think its D

  3. mckenzieandjesus
    • one year ago
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    What is the center and radius of the circle with equation (x - 5)2 + (y + 3)2 = 16? center (3, -5); radius = 4 center (-5, 3); radius = 16 center (5, -3); radius = 16 center (5, -3); radius = 4 my answer

  4. phi
    • one year ago
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    (x - 5)^2 + (y - -3)^2 = 4^2 has a center x=5 , y= -3 , r=4

  5. phi
    • one year ago
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    For the the first question, it looks like the circle in the graph has a radius of 1 and a center at x=-3 y=1 (-3, 1) put those numbers into \[ (x- h)^2 + (y -k)^2 = r^2 \]

  6. DecentNabeel
    • one year ago
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    the center is (5,-3) and radius is=4 the standard equation of the circle is. (x−h)2+(y−k)2=r2 h,k are center and r is the radius

  7. mckenzieandjesus
    • one year ago
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    @LynFran are u sure the first one is C?

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