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mckenzieandjesus
 one year ago
did i do this right?
What is the standard form of the equation of the circle in the graph?
(x  3)2 + (y + 1)2 = 1
(x + 3)2 + (y  1)2 = 2
(x + 3)2 + (y  1)2 = 1
(x  3)2 + (y + 1)2 = 2
mckenzieandjesus
 one year ago
did i do this right? What is the standard form of the equation of the circle in the graph? (x  3)2 + (y + 1)2 = 1 (x + 3)2 + (y  1)2 = 2 (x + 3)2 + (y  1)2 = 1 (x  3)2 + (y + 1)2 = 2

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mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0i think its D

mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0What is the center and radius of the circle with equation (x  5)2 + (y + 3)2 = 16? center (3, 5); radius = 4 center (5, 3); radius = 16 center (5, 3); radius = 16 center (5, 3); radius = 4 my answer

phi
 one year ago
Best ResponseYou've already chosen the best response.0(x  5)^2 + (y  3)^2 = 4^2 has a center x=5 , y= 3 , r=4

phi
 one year ago
Best ResponseYou've already chosen the best response.0For the the first question, it looks like the circle in the graph has a radius of 1 and a center at x=3 y=1 (3, 1) put those numbers into \[ (x h)^2 + (y k)^2 = r^2 \]

DecentNabeel
 one year ago
Best ResponseYou've already chosen the best response.0the center is (5,3) and radius is=4 the standard equation of the circle is. (x−h)2+(y−k)2=r2 h,k are center and r is the radius

mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0@LynFran are u sure the first one is C?
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