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anonymous
 one year ago
When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed?
2 Al + 6HCl → 2 AlCl3 + 3 H2
anonymous
 one year ago
When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed? 2 Al + 6HCl → 2 AlCl3 + 3 H2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know I need to balance the equation first.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06Al + 18HCl > 6AlCl3 + 9H2

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2It was already balanced to begin with

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so how do i find limiting reactant and # of moles of H2 that can be formed

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.2You find the limiting reagent by finding which ever one needs the least amount of moles to produce your product. Keeping in mind that your coefficients need to be taken into account

TrojanPoem
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435565108958:dw

TrojanPoem
 one year ago
Best ResponseYou've already chosen the best response.0so HCL is limiting the reaction as it need to be more to react with all the AL , the current amount can only react with approximately 4.3 moles. Now we have to solve for H2 which will be formed.

TrojanPoem
 one year ago
Best ResponseYou've already chosen the best response.0To do so we will make use of HCl ( the least amount) or we will get excessive number more than we will really get. dw:1435565479220:dw

TrojanPoem
 one year ago
Best ResponseYou've already chosen the best response.0so we have 6  4.3 = 1.7 moles excessive of AL and 6.5 moles of H2 will be formed
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