anonymous
  • anonymous
When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed? 2 Al + 6HCl → 2 AlCl3 + 3 H2
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@dan815
anonymous
  • anonymous
@abb0t
anonymous
  • anonymous
Please help guys

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I know I need to balance the equation first.
anonymous
  • anonymous
6Al + 18HCl -> 6AlCl3 + 9H2
taramgrant0543664
  • taramgrant0543664
It was already balanced to begin with
anonymous
  • anonymous
ok so how do i find limiting reactant and # of moles of H2 that can be formed
taramgrant0543664
  • taramgrant0543664
You find the limiting reagent by finding which ever one needs the least amount of moles to produce your product. Keeping in mind that your coefficients need to be taken into account
TrojanPoem
  • TrojanPoem
|dw:1435565108958:dw|
TrojanPoem
  • TrojanPoem
so HCL is limiting the reaction as it need to be more to react with all the AL , the current amount can only react with approximately 4.3 moles. Now we have to solve for H2 which will be formed.
TrojanPoem
  • TrojanPoem
To do so we will make use of HCl ( the least amount) or we will get excessive number more than we will really get. |dw:1435565479220:dw|
TrojanPoem
  • TrojanPoem
so we have 6 - 4.3 = 1.7 moles excessive of AL and 6.5 moles of H2 will be formed

Looking for something else?

Not the answer you are looking for? Search for more explanations.