A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed? 2 Al + 6HCl → 2 AlCl3 + 3 H2

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @dan815

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @abb0t

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Please help guys

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I know I need to balance the equation first.

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    6Al + 18HCl -> 6AlCl3 + 9H2

  6. taramgrant0543664
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    It was already balanced to begin with

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so how do i find limiting reactant and # of moles of H2 that can be formed

  8. taramgrant0543664
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    You find the limiting reagent by finding which ever one needs the least amount of moles to produce your product. Keeping in mind that your coefficients need to be taken into account

  9. TrojanPoem
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1435565108958:dw|

  10. TrojanPoem
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so HCL is limiting the reaction as it need to be more to react with all the AL , the current amount can only react with approximately 4.3 moles. Now we have to solve for H2 which will be formed.

  11. TrojanPoem
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    To do so we will make use of HCl ( the least amount) or we will get excessive number more than we will really get. |dw:1435565479220:dw|

  12. TrojanPoem
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so we have 6 - 4.3 = 1.7 moles excessive of AL and 6.5 moles of H2 will be formed

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.