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anonymous

  • one year ago

WILL MEDAL AND FAN!! NEED HELP ASAP!! PLEASE!! Describe the graph x3-18x2+101x-180. Find the y and x intercepts

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  1. anonymous
    • one year ago
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    @mathstudent55 @astrophysics @KEYS

  2. anonymous
    • one year ago
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    Please anyone

  3. anonymous
    • one year ago
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    @owlcoffee

  4. anonymous
    • one year ago
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    Hi!!

  5. Owlcoffee
    • one year ago
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    \[f:f(x)=x ^{3}-18x^2+101x-180\] Before I bI+ll describe to you why I put the "f:f(x)" there. Very simple, because a graph is but a bunch of points set up in a reference system, where x increases, the value of y will be dependant on the value of "x" that we take in consideration, therefore, the "function" describes the behavior of these points. There are some notable points that most functions have in their composition, which are: (1) The y-intercept (2)The x-interception, often called "zeroes" or "roots". The "y-intercept" is the notable point of the function where the "x" value is zero, therefore, we will take the function and replace all the "x's" with "0's" and that will allow us to know where in the y-axis the point is situated: \[f:f(0)=(0)^3-18(0)^2+101(0)-180\] I'll leave the calculations to you. The "x" interception is a little more complex, but very linear concept, but these notable or notable points have the definition of nullifying the function, meaning that we want to know the values of "x" that make the whole function equal zero: \[x ^{3}-18x^2+101x-180 =0\]

  6. anonymous
    • one year ago
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    Is the y intercept (0,-180)

  7. anonymous
    • one year ago
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    @owlcoffee

  8. anonymous
    • one year ago
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    @phi

  9. anonymous
    • one year ago
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    @LynFan please help😊

  10. LynFran
    • one year ago
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    ok to find the x intercept we let y=0 to find the y intercept we let x=0 and yours y intercept is correct...

  11. anonymous
    • one year ago
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    OK so whatvabout the xintercept?

  12. LynFran
    • one year ago
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    let y=0 and solve for x ok

  13. anonymous
    • one year ago
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    Ok so would it be (-1,0)

  14. LynFran
    • one year ago
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    \[x ^{3}-18x ^{2}+101x-180=0\]

  15. anonymous
    • one year ago
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    So would there be multiply x intercepts

  16. anonymous
    • one year ago
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    Is it 3x+36x-101x-180

  17. anonymous
    • one year ago
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    I'm sorry I'm not getting this😥

  18. anonymous
    • one year ago
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    Thank you

  19. anonymous
    • one year ago
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    Would the intercepts be (-1,0) (2,0)

  20. anonymous
    • one year ago
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    @LynFan yes?

  21. LynFran
    • one year ago
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    (5,0), (4,0), (9,0) and (0,-180) the solution to y intercept also... https://www.symbolab.com/solver/algebra-calculator/0%5E%7B3%7D-18%5Cleft(0%5Cright)%5E%7B2%7D%2B101%5Cleft(0%5Cright)-180%3Dy/?origin=button

  22. anonymous
    • one year ago
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    Can u showvme how u found that on here? It won't open on my browser

  23. LynFran
    • one year ago
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    what r u talking about...how i find what?

  24. anonymous
    • one year ago
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    The x intercept

  25. LynFran
    • one year ago
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    i type the complete equation here... https://www.symbolab.com/solver/algebra-calculator/x%5E%7B3%7D-18x%5E%7B2%7D%2B101x-180%3D0/?origin=button and the calculator solve for x intercept

  26. anonymous
    • one year ago
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    It won't work BC it says I have to pay for it

  27. anonymous
    • one year ago
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    Can u just write it here without the link

  28. LynFran
    • one year ago
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    ok the first step to do is to factor the equation

  29. LynFran
    • one year ago
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    \[x ^{3}-18x ^{2}+101x-180=0\]when factored we get\[(x-4)(x-5)(x-9)=0\] we then let each bracket=0 since they are product of each other..\[(x-4)=0\]\[(x-5)=0\]\[(x-9)=0\]..so \[x=4\]\[x=5\]\[x=9\]

  30. anonymous
    • one year ago
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    Then howvwould u graph thaylt

  31. anonymous
    • one year ago
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    Can u graph that?

  32. anonymous
    • one year ago
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    Wouldn't it u use Descartes sign rule?

  33. anonymous
    • one year ago
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    Wouldn't it u use Descartes sign rule?

  34. LynFran
    • one year ago
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  35. anonymous
    • one year ago
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    Ahhhh that you!!!!

  36. anonymous
    • one year ago
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    Thank you!!

  37. LynFran
    • one year ago
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    welcome

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