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anonymous

  • one year ago

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°.

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. triciaal
    • one year ago
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    use what he just told you x = r cos theta and y = r sin theta between 0 and 2 pi

  3. jim_thompson5910
    • one year ago
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    well I think we're going in reverse now

  4. jim_thompson5910
    • one year ago
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    I think they are asking "if (x,y) = (3,-3), then what is (r,theta)?"

  5. anonymous
    • one year ago
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    Isn't there a formula to go from this to polar

  6. triciaal
    • one year ago
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    |dw:1435543120658:dw|

  7. anonymous
    • one year ago
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    yes

  8. jim_thompson5910
    • one year ago
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    \[\Large r = \sqrt{x^2 + y^2}\] \[\Large \theta = \arctan\left(\frac{y}{x}\right)\]

  9. anonymous
    • one year ago
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    thanks

  10. jim_thompson5910
    • one year ago
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    yw

  11. anonymous
    • one year ago
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    that is also known as tan^-1 correct? @jim_thompson5910

  12. jim_thompson5910
    • one year ago
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    yeah arctan, tan^(-1), and inverse tan are all the same thing

  13. anonymous
    • one year ago
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    thanks, i got one more @jim_thompson5910

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spraguer (Moderator)
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