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anonymous
 one year ago
Dylan solved the exponential equation 3x+1 = 15 and his work is shown below. What is the first step he did incorrectly?
Step 1: log3x+1 = log15
Step 2: 3 log(x + 1) = log15
Step 3: log(x + 1) = log 15 over 3
Step 4: log(x + 1) = 0.3920304
Step 5: ln[log(x + 1)] = ln0.3920304
Step 6: x + 1 = −0.936415
Step 7: x = −1.936415
I know it's either step 2 or step 3. This is just all so confusing to me...
anonymous
 one year ago
Dylan solved the exponential equation 3x+1 = 15 and his work is shown below. What is the first step he did incorrectly? Step 1: log3x+1 = log15 Step 2: 3 log(x + 1) = log15 Step 3: log(x + 1) = log 15 over 3 Step 4: log(x + 1) = 0.3920304 Step 5: ln[log(x + 1)] = ln0.3920304 Step 6: x + 1 = −0.936415 Step 7: x = −1.936415 I know it's either step 2 or step 3. This is just all so confusing to me...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x+1 is in the exponent, like that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(3^{x+1}=15\) I would divide by 3 first, \(3^{x}=5\) then, log base 3, \(\log_33^{x}=\log_35\) \(x\log_33=\log_35\) \(x=\log_35\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is what I see as the quickest approach to the exact solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, I will tell you what though....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in other words, \(\Large \log(A^B)~~\ne~~ A~\log(B)\) BUT, \(\Large \log(A^B)~~\ne~~ B~\log(A)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in other words, the exponent in log, goes outside the log.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the \(\underline{\rm exponent}\)!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so what step is incorrect ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, if step 3, right side, says `log(15/3)` and not `(log 15)/3`, then step 3 is incorrect as well.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but how can something be correct if mistake is already made?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, step 3, if you assume step 2 is given, is right.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2@fakeee \(\Large \log(A^B)~~\ne~~ A~\log(B)\) Yes!! \(\Large \log(A^B)~~\ne~~ B~\log(A)\) NNNNNNNNNO

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2Because \(\Large \log(A^B)~~=~~ B~\log(A)\)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.2For example: \(\Large \log(10^2)~~=~~ 2~\log(10)=2\) or \(\Large \log(100)~~=2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I meant to say that 2nd eq. is = (not \(\ne\)) apologize... Thanks Loser...(don't mean to offend you xD)
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