anonymous
  • anonymous
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
your part 1 is correct, but part 2 is not

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jim_thompson5910
  • jim_thompson5910
|dw:1435541483644:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435541514136:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435541555572:dw|
jim_thompson5910
  • jim_thompson5910
The period T is found through the formula T = 2pi/B
jim_thompson5910
  • jim_thompson5910
do you see how to find T?
anonymous
  • anonymous
no not really
jim_thompson5910
  • jim_thompson5910
If you're stuck, then \[\Large T = \frac{2\pi}{B}\] \[\Large T = \frac{2\pi}{\frac{\pi}{15}}\] \[\Large T = \frac{\frac{2\pi}{1}}{\frac{\pi}{15}}\] \[\Large T = \frac{2\pi}{1}\times\frac{15}{\pi}\] \[\Large T = ??\]
anonymous
  • anonymous
t=30pi/pi???
jim_thompson5910
  • jim_thompson5910
the pi's will cancel
anonymous
  • anonymous
so 30
jim_thompson5910
  • jim_thompson5910
yep, the period is 30 seconds that means it takes 30 seconds for the wheel to do one full cycle
jim_thompson5910
  • jim_thompson5910
in part 1, you should NOT have cos/( it should be cos( there is no division sign between the "cos" and the opening parenthesis
jim_thompson5910
  • jim_thompson5910
I noticed that just now. But everything else in part 1 looks good
anonymous
  • anonymous
can i do part three and you check?
jim_thompson5910
  • jim_thompson5910
sure
anonymous
  • anonymous
actually can you help because i have no idea where to start..
jim_thompson5910
  • jim_thompson5910
we can graph the h(t) function using desmos. That's probably the easiest way an alternative is to remember that cos(x) has a min of -1. That's the smallest output cosine can give
jim_thompson5910
  • jim_thompson5910
since the smallest output is -1, you can replace the cos(pi/15t) with -1 and evaluate
anonymous
  • anonymous
so itd be cos((pi/15)-1)? orrrr
anonymous
  • anonymous
20cos((pi/15)-1)+30?
jim_thompson5910
  • jim_thompson5910
\[\Large 20*\cos\left(\frac{\pi}{15}t\right) + 30\] \[\Large 20*(-1) + 30 = ??\]
jim_thompson5910
  • jim_thompson5910
I replaced all of the cosine with -1
anonymous
  • anonymous
hang on ill brb i have to take my dog out
jim_thompson5910
  • jim_thompson5910
ok
anonymous
  • anonymous
okay back lemme look
anonymous
  • anonymous
870?
anonymous
  • anonymous
or 49? do you add -1 to 30 and then add 20 or?
anonymous
  • anonymous
PEMDAS so multiply then add so 20*-1 -20+30=10
jim_thompson5910
  • jim_thompson5910
20(-1)+30 = 10, yes
jim_thompson5910
  • jim_thompson5910
that means the lowest on the Ferris wheel is 10 ft off the ground
anonymous
  • anonymous
Thank you!
jim_thompson5910
  • jim_thompson5910
no problem

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