anonymous
  • anonymous
Find the surface area of a pyramid if its height is 4 cm and its base is a rectangle with side lengths 4 cm and 6 cm. Round to the nearest whole number.
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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jim_thompson5910
  • jim_thompson5910
What is the area of the base?
anonymous
  • anonymous
24 cm^2
jim_thompson5910
  • jim_thompson5910
correct

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More answers

jim_thompson5910
  • jim_thompson5910
|dw:1435548018859:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435548042782:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435548055051:dw|
jim_thompson5910
  • jim_thompson5910
do you see how I got that triangle I just added?
anonymous
  • anonymous
yes
jim_thompson5910
  • jim_thompson5910
it's a right triangle with legs 3 and 4 the hypotenuse is what?
anonymous
  • anonymous
5
jim_thompson5910
  • jim_thompson5910
|dw:1435548291256:dw|
jim_thompson5910
  • jim_thompson5910
we will have 2 triangles on the lateral face of the pyramid that look like this |dw:1435548321950:dw| base = 4 height = 5
jim_thompson5910
  • jim_thompson5910
what is the area of that triangle?
anonymous
  • anonymous
10cm^2
jim_thompson5910
  • jim_thompson5910
there are 2 of these triangles, so they add to 10+10 = 20 cm^2 the front and back faces |dw:1435548418230:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435548440907:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435548484189:dw|
anonymous
  • anonymous
So for the other 2 sides would the area be 15cm^2.
anonymous
  • anonymous
15+15=30cm^2
jim_thompson5910
  • jim_thompson5910
how are you getting 15?
anonymous
  • anonymous
And the bottom area would be 6x4=24cm^2
anonymous
  • anonymous
I got 15 from multiplying 6x5=30/2=15cm^2. Would that not be correct?
jim_thompson5910
  • jim_thompson5910
that other hypotenuse isn't 5
jim_thompson5910
  • jim_thompson5910
|dw:1435548754459:dw|
anonymous
  • anonymous
4.47
jim_thompson5910
  • jim_thompson5910
so you have 2 more triangles, each looking like this |dw:1435548837682:dw|
anonymous
  • anonymous
Would i make 4.47 into 4 because the problem says to round the nearest whole number.
jim_thompson5910
  • jim_thompson5910
round when you're done calculating
jim_thompson5910
  • jim_thompson5910
so it might be better to use more decimal digits instead of 4.47 maybe use 4.47213595 or something \[\Large \sqrt{20} \approx 4.47213595\]
anonymous
  • anonymous
Area=13.416407
jim_thompson5910
  • jim_thompson5910
that's the area of one triangle there are 2 of them
anonymous
  • anonymous
26.832814cm^2
jim_thompson5910
  • jim_thompson5910
Summary: you have a base that's 24 cm^2 the front and back triangles have a total area of 20cm^2 the left and right triangles have a total area of 26.832814 cm^2
anonymous
  • anonymous
The answer would be then 70.83 or 71cm^2 (the answer was in my book but i couldn't see what i was doing wrong THANK YOU SO MUCH :D)
jim_thompson5910
  • jim_thompson5910
you're welcome

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