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anonymous

  • one year ago

Find the surface area of a pyramid if its height is 4 cm and its base is a rectangle with side lengths 4 cm and 6 cm. Round to the nearest whole number.

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  1. jim_thompson5910
    • one year ago
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    What is the area of the base?

  2. anonymous
    • one year ago
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    24 cm^2

  3. jim_thompson5910
    • one year ago
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    correct

  4. jim_thompson5910
    • one year ago
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    |dw:1435548018859:dw|

  5. jim_thompson5910
    • one year ago
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    |dw:1435548042782:dw|

  6. jim_thompson5910
    • one year ago
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    |dw:1435548055051:dw|

  7. jim_thompson5910
    • one year ago
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    do you see how I got that triangle I just added?

  8. anonymous
    • one year ago
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    yes

  9. jim_thompson5910
    • one year ago
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    it's a right triangle with legs 3 and 4 the hypotenuse is what?

  10. anonymous
    • one year ago
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    5

  11. jim_thompson5910
    • one year ago
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    |dw:1435548291256:dw|

  12. jim_thompson5910
    • one year ago
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    we will have 2 triangles on the lateral face of the pyramid that look like this |dw:1435548321950:dw| base = 4 height = 5

  13. jim_thompson5910
    • one year ago
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    what is the area of that triangle?

  14. anonymous
    • one year ago
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    10cm^2

  15. jim_thompson5910
    • one year ago
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    there are 2 of these triangles, so they add to 10+10 = 20 cm^2 the front and back faces |dw:1435548418230:dw|

  16. jim_thompson5910
    • one year ago
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    |dw:1435548440907:dw|

  17. jim_thompson5910
    • one year ago
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    |dw:1435548484189:dw|

  18. anonymous
    • one year ago
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    So for the other 2 sides would the area be 15cm^2.

  19. anonymous
    • one year ago
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    15+15=30cm^2

  20. jim_thompson5910
    • one year ago
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    how are you getting 15?

  21. anonymous
    • one year ago
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    And the bottom area would be 6x4=24cm^2

  22. anonymous
    • one year ago
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    I got 15 from multiplying 6x5=30/2=15cm^2. Would that not be correct?

  23. jim_thompson5910
    • one year ago
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    that other hypotenuse isn't 5

  24. jim_thompson5910
    • one year ago
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    |dw:1435548754459:dw|

  25. anonymous
    • one year ago
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    4.47

  26. jim_thompson5910
    • one year ago
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    so you have 2 more triangles, each looking like this |dw:1435548837682:dw|

  27. anonymous
    • one year ago
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    Would i make 4.47 into 4 because the problem says to round the nearest whole number.

  28. jim_thompson5910
    • one year ago
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    round when you're done calculating

  29. jim_thompson5910
    • one year ago
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    so it might be better to use more decimal digits instead of 4.47 maybe use 4.47213595 or something \[\Large \sqrt{20} \approx 4.47213595\]

  30. anonymous
    • one year ago
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    Area=13.416407

  31. jim_thompson5910
    • one year ago
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    that's the area of one triangle there are 2 of them

  32. anonymous
    • one year ago
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    26.832814cm^2

  33. jim_thompson5910
    • one year ago
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    Summary: you have a base that's 24 cm^2 the front and back triangles have a total area of 20cm^2 the left and right triangles have a total area of 26.832814 cm^2

  34. anonymous
    • one year ago
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    The answer would be then 70.83 or 71cm^2 (the answer was in my book but i couldn't see what i was doing wrong THANK YOU SO MUCH :D)

  35. jim_thompson5910
    • one year ago
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    you're welcome

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