anonymous
  • anonymous
What is the sum of a 7-term geometric series if the first term is 6, the last term is 24,576, and the common ratio is 4? −32,766 −19,662 19,662 32,766
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
i got -32, 766
jim_thompson5910
  • jim_thompson5910
\[\Large S_n = a*\frac{1-r^n}{1-r}\] Plug in a = 6 (first term) r = 4 (common ratio) n = 7 (number of terms)

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More answers

anonymous
  • anonymous
6* 1-4^7/1-4?
jim_thompson5910
  • jim_thompson5910
I think you meant this right? \[\Large 6*\frac{1-4^7}{1-4}\]
anonymous
  • anonymous
yeah!
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
compute that with a calculator
jim_thompson5910
  • jim_thompson5910
make sure you use parenthesis
anonymous
  • anonymous
i got 32766
jim_thompson5910
  • jim_thompson5910
same here
anonymous
  • anonymous
thanks again
jim_thompson5910
  • jim_thompson5910
np
anonymous
  • anonymous
will you check this one? @jim_thompson5910
anonymous
  • anonymous
What is the sum of the geometric sequence 1, −6, 36, … if there are 7 terms? −39,991 −6,665 6,665 39,991 x this one?
jim_thompson5910
  • jim_thompson5910
Yep \[\Large S_n = a*\frac{1-r^n}{1-r}\] \[\Large S_7 = 1*\frac{1-(-6)^7}{1-(-6)}\] \[\Large S_7 = 39,991\]

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