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anonymous

  • one year ago

What is the sum of a 7-term geometric series if the first term is 6, the last term is 24,576, and the common ratio is 4? −32,766 −19,662 19,662 32,766

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. anonymous
    • one year ago
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    i got -32, 766

  3. jim_thompson5910
    • one year ago
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    \[\Large S_n = a*\frac{1-r^n}{1-r}\] Plug in a = 6 (first term) r = 4 (common ratio) n = 7 (number of terms)

  4. anonymous
    • one year ago
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    6* 1-4^7/1-4?

  5. jim_thompson5910
    • one year ago
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    I think you meant this right? \[\Large 6*\frac{1-4^7}{1-4}\]

  6. anonymous
    • one year ago
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    yeah!

  7. jim_thompson5910
    • one year ago
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    good

  8. jim_thompson5910
    • one year ago
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    compute that with a calculator

  9. jim_thompson5910
    • one year ago
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    make sure you use parenthesis

  10. anonymous
    • one year ago
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    i got 32766

  11. jim_thompson5910
    • one year ago
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    same here

  12. anonymous
    • one year ago
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    thanks again

  13. jim_thompson5910
    • one year ago
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    np

  14. anonymous
    • one year ago
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    will you check this one? @jim_thompson5910

  15. anonymous
    • one year ago
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    What is the sum of the geometric sequence 1, −6, 36, … if there are 7 terms? −39,991 −6,665 6,665 39,991 x this one?

  16. jim_thompson5910
    • one year ago
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    Yep \[\Large S_n = a*\frac{1-r^n}{1-r}\] \[\Large S_7 = 1*\frac{1-(-6)^7}{1-(-6)}\] \[\Large S_7 = 39,991\]

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