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anonymous

  • one year ago

What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

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  1. freckles
    • one year ago
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    An equation for a circle with center (h,k) and radius r is: \[(x-h)^2+(y-k)^2=r^2\] so plug in your h and k

  2. freckles
    • one year ago
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    then use the point on (-4,1) to plug into (x,y) since (-4,1) is on the circle to find r

  3. UsukiDoll
    • one year ago
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    don't we also have (h,k) for the center ?

  4. freckles
    • one year ago
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    yep that is the first step "plug in your h and k"

  5. UsukiDoll
    • one year ago
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    so since we have (-2,1) in the form of (h,k) we let h =-2, and k = 1

  6. freckles
    • one year ago
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    yes that is the h and k since my center of my equation I have above is (h,k) and the center of his is (-2,1) so yep he needs to replace h with -2 and k with 1

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