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anonymous

  • one year ago

Factor the following expression 18u^3v^2x^6−12u^7v^8

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  1. anonymous
    • one year ago
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    Oops - it should be 3u^9v^4w^3+15u^2v^5

  2. myininaya
    • one year ago
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    Hi. @Juliette2120 do you know the greatest common factor of 18 and 12?

  3. myininaya
    • one year ago
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    oh sorry didn't see the new problem.

  4. myininaya
    • one year ago
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    Do you know the greatest common factor of 3 and 15?

  5. myininaya
    • one year ago
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    if I write 15 as 3(5) and you compare 3 to 3(5) can you tell me the factors that 3 and 3(5) have in common?

  6. anonymous
    • one year ago
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    3 is the greatest common factor

  7. myininaya
    • one year ago
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    yes now let's look at the u's of each term \[3u^9v^4w^3+15u^2v^5\\ 3(u^9v^4w^3+5u^2v^5)\] so this is what we have now but we can factor out more than just what we factored out

  8. myininaya
    • one year ago
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    now looking at the u part... we have u^9 and u^2

  9. myininaya
    • one year ago
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    \[u^9=u^2 \cdot u^7\] what factors does \[u^2 \cdot u^7 \text{ and } u^2 \text{ have in common }\]

  10. myininaya
    • one year ago
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    let me know if you are having trouble?

  11. anonymous
    • one year ago
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    Sorry! OS won't seem to let me post my replies!

  12. myininaya
    • one year ago
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    I guess it let's you reply after refreshing the page ? Or do you have to completely leave and come back to post a reply? I'm on google chrome and haven o problems. Maybe you can try that internet browser.

  13. anonymous
    • one year ago
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    I think I was able to figure this out. Thank you very much for your help! Just the simplification sent me in the right direction.

  14. myininaya
    • one year ago
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    No problem.

  15. myininaya
    • one year ago
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    But we still needed to factor out a few more things.

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