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anonymous
 one year ago
Factor the following expression 18u^3v^2x^6−12u^7v^8
anonymous
 one year ago
Factor the following expression 18u^3v^2x^6−12u^7v^8

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oops  it should be 3u^9v^4w^3+15u^2v^5

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5Hi. @Juliette2120 do you know the greatest common factor of 18 and 12?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5oh sorry didn't see the new problem.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5Do you know the greatest common factor of 3 and 15?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5if I write 15 as 3(5) and you compare 3 to 3(5) can you tell me the factors that 3 and 3(5) have in common?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03 is the greatest common factor

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5yes now let's look at the u's of each term \[3u^9v^4w^3+15u^2v^5\\ 3(u^9v^4w^3+5u^2v^5)\] so this is what we have now but we can factor out more than just what we factored out

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5now looking at the u part... we have u^9 and u^2

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5\[u^9=u^2 \cdot u^7\] what factors does \[u^2 \cdot u^7 \text{ and } u^2 \text{ have in common }\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5let me know if you are having trouble?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry! OS won't seem to let me post my replies!

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5I guess it let's you reply after refreshing the page ? Or do you have to completely leave and come back to post a reply? I'm on google chrome and haven o problems. Maybe you can try that internet browser.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I was able to figure this out. Thank you very much for your help! Just the simplification sent me in the right direction.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.5But we still needed to factor out a few more things.
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