anonymous
  • anonymous
PLEASE HELP!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
@rvc

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jim_thompson5910
  • jim_thompson5910
|dw:1435553678935:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435553726945:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435553739818:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435553776029:dw|
jim_thompson5910
  • jim_thompson5910
what is x^2 times x^2
anonymous
  • anonymous
x^4
anonymous
  • anonymous
so what do I do now?
jim_thompson5910
  • jim_thompson5910
so we have \[\LARGE \sqrt[3]{x^4}\]
jim_thompson5910
  • jim_thompson5910
\[\LARGE \sqrt[3]{x^4} = \sqrt[3]{x^3*x}\] \[\LARGE \sqrt[3]{x^4} = \sqrt[3]{x^3}*\sqrt[3]{x}\] \[\LARGE \sqrt[3]{x^4} = ???\]
anonymous
  • anonymous
I'm not sure
jim_thompson5910
  • jim_thompson5910
the cube root of x^3 is x
jim_thompson5910
  • jim_thompson5910
it's like the square root of x^2 = x
anonymous
  • anonymous
oh, so it's \[x \sqrt[3]{x}\] ?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
ok thank you soon much :) <3
jim_thompson5910
  • jim_thompson5910
no problem

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