- ganeshie8

Stacy prepared 20 different letters to be sent to 20 addresses. For each letter she prepared an envelope with its correct address. If the 20 letters to be put in to 20 envelopes at random, what is the probability that exactly 19 letters will be put in to the envelope with the correct address?

- jamiebookeater

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- perl

.

- ikram002p

(1/20)^19 ?

- perl

If 19 letters are in the correct envelopes, then the last letter must also be in the correct envelope.
The probability of all 20 envelopes in the correct order is 1/20!

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## More answers

- ikram002p

:O

- dan815

yes i agree!

- dan815

total possibilties - prob of 1 wrong, and prob of 0 wrong

- ganeshie8

yeah that looks pretty neat, i guess then we can conclude the probability for exactly 19 letters putting in correct envelopes is 0 ?

- dan815

oh wait lol everything is wring oops xD

- anonymous

@dan815 Could you help with this math question

- dan815

everything is right*

- ikram002p

xD

- dan815

the probabilitly is 0!

- perl

oh its impossible :)

- dan815

trying to trick us -.-

- dan815

shame on this question

- ganeshie8

guess i was partially successful :P

- dan815

lol

- ikram002p

-.-

- anonymous

Hello

- perl

What about 19 or above

- anonymous

Could someone Help me http://openstudy.com/study#/updates/55912961e4b0428366270957

- perl

At least 19 correct

- ikram002p

im half a sleep anyway xD

- perl

Then it would be 1/20!

- anonymous

You guys are so mean Please Help :(
Could someone Help me
http://openstudy.com/study#/updates/55912961e4b0428366270957

- ganeshie8

total permutations : 20!
permutations in favor : 1
so yeah.. 1/20!
on cursory thinking, this doesn't look like a binomial distribution, so other cases can get complicated hmm

- ikram002p

try 10 to be correct ?

- Loser66

Question: you have 20 envelopes and 20 letters; 19 are correct matching. Is it not that 20 are matching?? Since 19 right, how can the rest is wrong?

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