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If 19 letters are in the correct envelopes, then the last letter must also be in the correct envelope. The probability of all 20 envelopes in the correct order is 1/20!
yes i agree!
total possibilties - prob of 1 wrong, and prob of 0 wrong
yeah that looks pretty neat, i guess then we can conclude the probability for exactly 19 letters putting in correct envelopes is 0 ?
oh wait lol everything is wring oops xD
everything is right*
the probabilitly is 0!
oh its impossible :)
trying to trick us -.-
shame on this question
guess i was partially successful :P
What about 19 or above
At least 19 correct
im half a sleep anyway xD
Then it would be 1/20!
total permutations : 20! permutations in favor : 1 so yeah.. 1/20! on cursory thinking, this doesn't look like a binomial distribution, so other cases can get complicated hmm
try 10 to be correct ?
Question: you have 20 envelopes and 20 letters; 19 are correct matching. Is it not that 20 are matching?? Since 19 right, how can the rest is wrong?