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anonymous
 one year ago
The cost in dollars to produce x cups of lemonade is represented by the function C(x) = 10 + 0.20x. The revenue in dollars earned by selling x cups of lemonade is represented by the function R(x) = 0.50x. What is the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost?
anonymous
 one year ago
The cost in dollars to produce x cups of lemonade is represented by the function C(x) = 10 + 0.20x. The revenue in dollars earned by selling x cups of lemonade is represented by the function R(x) = 0.50x. What is the minimum number of whole cups of lemonade that must be sold for the revenue to exceed the cost?

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perl
 one year ago
Best ResponseYou've already chosen the best response.0Please show any work you have done so far.

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1from the problem, we are given: revenue = R(x) = 0.50x cost = C(x) = 10 + 0.20x x = # of cups of lemonade for "revenue to exceed costs", this means revenue > costs, giving us the inequality 0.5x > 10 + 0.20x since we want to know the number of cups of lemonade that we need for revenue to exceed costs, we solve the inequality for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i got that also its just im stuck with the (>)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh nevermind thank you!
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