I need help on the first few steps, I'm not to sure how to do this. A vat of milk has spilled on a tile floor. The milk flow can be expressed with the function r(t) = 4t, where t represents time in minutes and r represents how far the milk is spreading. The spilled milk is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2.

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I need help on the first few steps, I'm not to sure how to do this. A vat of milk has spilled on a tile floor. The milk flow can be expressed with the function r(t) = 4t, where t represents time in minutes and r represents how far the milk is spreading. The spilled milk is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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A vat of milk has spilled on a tile floor. The milk flow can be expressed with the function r(t) = 4t, where t represents time in minutes and r represents how far the milk is spreading. The spilled milk is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2. Part A: Find the area of the circle of spilled milk as a function of time, or A[r(t)]. Show your work. (6 points) Part B: How large is the area of spilled milk after 4 minutes? You may use 3.14 to approximate π in this problem. (4 points)
Whole problem, but just need help getting through the first one then maybe I'll understand it.
substitute for r = 4t in A(r) = pi r^2

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so A = pi (4t)^2
= 16 pi t^2
Ok, so after I do that I would times t^2? Or would I leave it alone and times it by 3.14?
I know I would have to do the rate of change for the second part, but would it just be 3.14 times 16?
thats the answer to Part A for Part B plug in t = 4 into 16 pi t^2 and work it out.
Oh ok give me a moment
welshfella can u help me with a question?
16 pi (4)^2 16 pi (16) 16 (50.24) 803.84 This is what I got, not to sure if it's right or wrong.
was it right??
And yes it was sorry for missing your comment haven't been on

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