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anonymous

  • one year ago

Given: Line PB tangent Line PV, Line PU Secants If m Arch VU = 70° and m Arch ST = 30°, then m Angle 2 = a) 20 b) 35 c) 50

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  1. anonymous
    • one year ago
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    https://suwannee.owschools.com/media/g_geo_2013/7/group180.gif

  2. anonymous
    • one year ago
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    The answer I got wrong was 35

  3. phi
    • one year ago
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    average of the two arcs

  4. anonymous
    • one year ago
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    So, add them together and divide by two?

  5. phi
    • one year ago
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    yes

  6. anonymous
    • one year ago
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    Okay sorry it took so long

  7. anonymous
    • one year ago
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    I was Driving off a stalker

  8. anonymous
    • one year ago
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    I don't think you wanna' know what he said to me either

  9. anonymous
    • one year ago
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    :(

  10. anonymous
    • one year ago
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    I'm not worried or anything. Just annoyed

  11. anonymous
    • one year ago
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    @phi

  12. phi
    • one year ago
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    Report them if it happens again

  13. anonymous
    • one year ago
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    I will

  14. anonymous
    • one year ago
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    Don't worry

  15. anonymous
    • one year ago
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    Oh and btw, there is another question that applies to the same picture

  16. anonymous
    • one year ago
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    @phi

  17. phi
    • one year ago
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    if it asks for angle 1, that is 1/2 the difference of the two arcs i.e. (big - small)/2

  18. anonymous
    • one year ago
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    If m Angle 1 = 30° and m Arch ST = 20°, then m Arch VU = a) 10 b) 40 c) 80

  19. phi
    • one year ago
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    \[ \frac{VU- ST}{2} = Angle 1\]

  20. phi
    • one year ago
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    fill in what you know, then use algebra to "solve for VU" can you do that ?

  21. anonymous
    • one year ago
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    Hmmm. Let me think for a sec

  22. phi
    • one year ago
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    in the formula, replace ST with 20 and angle 1 with 30

  23. phi
    • one year ago
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    \[ \frac{VU- 20}{2} = 30 \] I would start by multiplying both sides by 2

  24. anonymous
    • one year ago
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    Yeah, I'm writing it down

  25. anonymous
    • one year ago
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    Oh and thanks. That helps

  26. anonymous
    • one year ago
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    I was thinking about doing that, but then I started to second guess myself

  27. anonymous
    • one year ago
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    So VU-40= 60?

  28. anonymous
    • one year ago
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    VU=100?

  29. phi
    • one year ago
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    you do this \[2\cdot \frac{(VU- 20)}{2} = 30 \cdot 2\] you can think of the left side as multiplying fraction times fraction (top times top and bottom times bottom) \[ \frac{2}{1} \cdot \frac{(VU- 20)}{2} = 30 \cdot 2\] \[\frac{2(VU- 20)}{2} = 30 \cdot 2\] or \[ \frac{2}{2} \frac{(VU- 20)}{1} = 30 \cdot 2\]

  30. phi
    • one year ago
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    in other words you should get VU -20 = 60

  31. anonymous
    • one year ago
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    Okay. So you don't multiply 20 by 2?

  32. anonymous
    • one year ago
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    I'm guessing that's where I messed up

  33. phi
    • one year ago
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    remember to how to add or subtract fractions: \[ \frac{VU}{2} - \frac{20}{2} = \frac{VU-20}{2} \] you can do it the other way round: \[ \frac{VU-20}{2}= \frac{VU}{2} - \frac{20}{2} \] and simplify 20/2 to 10 \[ \frac{VU}{2} - 10 = 30 \] now add 10 to both sides \[ \frac{VU}{2} - 10 +10 = 30+10 \\ \frac{VU}{2} = 40 \]

  34. anonymous
    • one year ago
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    So VU= 80

  35. phi
    • one year ago
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    yes.

  36. anonymous
    • one year ago
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    Alright I understand it now

  37. phi
    • one year ago
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    I guess you have to get the idea that \[ \frac{complicated\ stuff}{2} \cdot 2 = complicated\ stuff \]

  38. anonymous
    • one year ago
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    Hehehe. Lol!

  39. anonymous
    • one year ago
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    wow

  40. anonymous
    • one year ago
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    I'm gonna' be quoting that for awhile

  41. anonymous
    • one year ago
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    Thanks!

  42. phi
    • one year ago
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    yw

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