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anonymous

  • one year ago

Find x. Round to the nearest tenth if necessary. Assume that segments that appear to be tangent are tangent. x(x+5)=2(2+10)

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  1. misty1212
    • one year ago
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    HI!

  2. misty1212
    • one year ago
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    not clear what that tangent part means, but if it is \[x(x+5)=2(x+10)\] then when you multiply out you get \[x^2+5x=2x+20\]which is a quadratic

  3. misty1212
    • one year ago
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    set equal to zero \[x^2+3x-20=0\] then the quadratic formula

  4. anonymous
    • one year ago
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    then what would I do after that ? @misty1212

  5. misty1212
    • one year ago
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    do you know the quadratic formula?

  6. misty1212
    • one year ago
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    oh dang i made a mistake!!

  7. misty1212
    • one year ago
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    is this the original question \[x(x+5)=2(2+10)\]??

  8. misty1212
    • one year ago
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    if so, then it is just \[x^2+5x=24\]so \[x^2+5x-24=0\] a totally different equation

  9. misty1212
    • one year ago
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    this one is much easier factor as \[(x-3)(x+8)=0\] and now you can find the zeros easily

  10. anonymous
    • one year ago
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    yes! thank you @misty1212

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