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anonymous

  • one year ago

Divison in algebra?

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  1. anonymous
    • one year ago
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    \[x/3 - 1 = 1 - 3\]

  2. anonymous
    • one year ago
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    I don't really know how to start

  3. anonymous
    • one year ago
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    Do I add one on both sides? but then does it matter to which one I add one?

  4. anonymous
    • one year ago
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    okay that was dumb i guess it doesn't matter so then i have x/3 = 2 -3

  5. anonymous
    • one year ago
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    The simplest here is deal with right hand side first: 1-3 = -2

  6. anonymous
    • one year ago
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    ah yes i didn't think about that

  7. anonymous
    • one year ago
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    okay so x/2 - 1 = -2 and then i add one on both sides so x/2 = -1

  8. anonymous
    • one year ago
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    and then how do i fix that fraction :?

  9. anonymous
    • one year ago
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    Following that we deal with the left hand side: x/3 -1 , bring the -1 across to get : x/3 = -2 + 1 or x/3 = -1 and then simply cross multiply x/3 = -1 gives x= 3(-1) or x=-3

  10. anonymous
    • one year ago
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    um its x/2 :?

  11. anonymous
    • one year ago
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    x/2 = -1 gives x= 2(-1) or x=-2 okay i replaced the number and so the answer is -2 hmm trying to understand that x = 2(-1)

  12. anonymous
    • one year ago
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    |dw:1435457311312:dw|

  13. anonymous
    • one year ago
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    AH YES I SEE my book has taught me that so far for this silly SAT haha okay when i see something like x/2 = <-- bold -1 then that means to cross multiply yes so x/2 times -1/1 = 2(-1) and x(1) == x = -2 Thanks!!

  14. anonymous
    • one year ago
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    yeah thanks for the illustration :D

  15. anonymous
    • one year ago
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    Yo Welcome!

  16. anonymous
    • one year ago
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    OMG IM SO DUMB it wasss x/3 not x/2darn im so dumb sometimes lol like i copied the question too and forgot the variables xD

  17. anonymous
    • one year ago
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    so -3 haha..

  18. anonymous
    • one year ago
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    because i was looking at the answer choices like oh that's funny -2 isn't an option :I i'll get better haha

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