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anonymous

  • one year ago

Write an indirect proof to show that the diagonals of a parallelogram bisect one another. Be sure to create and name the appropriate geometric figures.

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  1. anonymous
    • one year ago
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    I really someone to help me!!

  2. anonymous
    • one year ago
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    @ganeshie8

  3. anonymous
    • one year ago
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    @Michele_Laino

  4. Michele_Laino
    • one year ago
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    step #1 in a parallelogram opposite side are congruent each other

  5. Michele_Laino
    • one year ago
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    |dw:1435597683771:dw|

  6. Michele_Laino
    • one year ago
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    since we can write: AD=BC

  7. Michele_Laino
    • one year ago
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    now we have this: |dw:1435597752477:dw| \[\begin{gathered} \angle DAM \simeq \angle MCB \hfill \\ \angle MBC \simeq \angle ADM \hfill \\ \end{gathered} \]

  8. Michele_Laino
    • one year ago
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    so the triangles ADM and BMC are congruent each other since the ASA criterion

  9. Michele_Laino
    • one year ago
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    in particular we have: \[\begin{gathered} AM \simeq MC \hfill \\ DM \simeq MB \hfill \\ \end{gathered} \] which represent the thesis of your problem

  10. anonymous
    • one year ago
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    wait... that's it?

  11. anonymous
    • one year ago
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    @Michele_Laino

  12. Michele_Laino
    • one year ago
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    yes!

  13. anonymous
    • one year ago
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    So how would I write out the problem?

  14. anonymous
    • one year ago
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    @Michele_Laino

  15. Michele_Laino
    • one year ago
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    you have to write my steps above @fighter23

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spraguer (Moderator)
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