## anonymous one year ago Write an indirect proof to show that the diagonals of a parallelogram bisect one another. Be sure to create and name the appropriate geometric figures.

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1. anonymous

I really someone to help me!!

2. anonymous

@ganeshie8

3. anonymous

@Michele_Laino

4. Michele_Laino

step #1 in a parallelogram opposite side are congruent each other

5. Michele_Laino

|dw:1435597683771:dw|

6. Michele_Laino

since we can write: AD=BC

7. Michele_Laino

now we have this: |dw:1435597752477:dw| $\begin{gathered} \angle DAM \simeq \angle MCB \hfill \\ \angle MBC \simeq \angle ADM \hfill \\ \end{gathered}$

8. Michele_Laino

so the triangles ADM and BMC are congruent each other since the ASA criterion

9. Michele_Laino

in particular we have: $\begin{gathered} AM \simeq MC \hfill \\ DM \simeq MB \hfill \\ \end{gathered}$ which represent the thesis of your problem

10. anonymous

wait... that's it?

11. anonymous

@Michele_Laino

12. Michele_Laino

yes!

13. anonymous

So how would I write out the problem?

14. anonymous

@Michele_Laino

15. Michele_Laino

you have to write my steps above @fighter23