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ashontae19
 one year ago
square root of 200 in standard form
ashontae19
 one year ago
square root of 200 in standard form

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xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1iroot(200)=10iroot(2)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1i is imaginary unit

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1\(\sqrt{200}=i\sqrt{200}=i10\sqrt{2}\)

ashontae19
 one year ago
Best ResponseYou've already chosen the best response.1oh ok i was correct i have no more if u dnt mind

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1squared by two what do you mean lol

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1post your other questions in different posts pls!!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0hint: we can write this: \[\Large  200 = 200\left\{ {\cos \left( {\pi + 2k\pi } \right) + i\sin \left( {\pi + 2k\pi } \right)} \right\}\]

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1polar form..

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1well do the same process you did with the first

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.17 you don't have to worry about

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1just root(96)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1how did root (96) simplify to 4?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0we have two square roots: \[\Large \begin{gathered} \sqrt {  200} = \sqrt {200} \left\{ {\cos \left( {\frac{\pi }{2} + k\pi } \right) + i\sin \left( {\frac{\pi }{2} + k\pi } \right)} \right\}, \hfill \\ \hfill \\ k = 0,1 \hfill \\ \end{gathered} \]

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1root(96)=root(16x6)=4root(6)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1oh you have root(6) my bad i miss read your reply

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0\[\Large \begin{gathered} \sqrt {  96} = \sqrt {96} \left\{ {\cos \left( {\frac{\pi }{2} + k\pi } \right) + i\sin \left( {\frac{\pi }{2} + k\pi } \right)} \right\}, \hfill \\ \hfill \\ k = 0,1 \hfill \\ \end{gathered} \]

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1your answer is good!

ashontae19
 one year ago
Best ResponseYou've already chosen the best response.1yes so i was correct?

ashontae19
 one year ago
Best ResponseYou've already chosen the best response.1thank youu i do not know which one to give medel to since yall both helped me

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1does not matter :)
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