anonymous
  • anonymous
The area of a rectangular piece of land is 260 square meters. If the length of the land was 5 meters less and the width was 2 meters more, the shape of the land would be a square. Part A: Write an equation to find the width (x) of the land. Show the steps of your work.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@SolomonZelman
SolomonZelman
  • SolomonZelman
Area = w × l
SolomonZelman
  • SolomonZelman
w × l = 260 l + 5 = w + 2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

SolomonZelman
  • SolomonZelman
do you get the first equation i posted ?
anonymous
  • anonymous
yes
SolomonZelman
  • SolomonZelman
ok, and the second equation is the second sentence. What the sentence is saying is that if: 1) length was 5 more (i.e. l+5) 2) width was 2 more (i.e. w+2) then the shape would have been a square. You know that in a square length and with are equal. And when length is l+5 and width is w+2, then it is a square. THEREFORE l+5=w+2
anonymous
  • anonymous
okay
anonymous
  • anonymous
so to find w or y the equation would be y=x+2+5 or y=x+7
SolomonZelman
  • SolomonZelman
the y ?
anonymous
  • anonymous
opps other way round.
SolomonZelman
  • SolomonZelman
w × l = 260 l + 5 = w + 2 all you need to do is to solve this system. l + 5 = w + 2 → l=w-3 so substitute w × (w-3) = 260 w² - 3w = 260
anonymous
  • anonymous
okay
SolomonZelman
  • SolomonZelman
solve for w (it will be a square root)
anonymous
  • anonymous
w is 13?
SolomonZelman
  • SolomonZelman
w²-3w-260=0 -(-3)±√[9-4(1)(260)] ---------------- 2(1) 3±√[1049] ---------------- 2
anonymous
  • anonymous
wait but shouldn't it be w + 2 = y - 5 ?
SolomonZelman
  • SolomonZelman
oh, tnx... my error
SolomonZelman
  • SolomonZelman
w × l = 260 l - 5 = w + 2 then, w × l = 260 l = w + 7
SolomonZelman
  • SolomonZelman
w × (w + 7) = 260
SolomonZelman
  • SolomonZelman
13 is right
anonymous
  • anonymous
so the equation for w is w = l - 7 ?
SolomonZelman
  • SolomonZelman
well, -7 or +7, just depending on how you define l and w, and which way you sub. but yes, there is an extra 7 between one dimension and the other dimension.
SolomonZelman
  • SolomonZelman
w × l = 260 l - 5 = w + 2 then, w × l = 260 l = w + 7 then, w × (w+7) = 260 then, w² + 7w = 260 then, w² + 7w - 260 = 0 (w + 20) (w - 13) = 0
SolomonZelman
  • SolomonZelman
so w=13
SolomonZelman
  • SolomonZelman
now, you nave to find l
anonymous
  • anonymous
20
SolomonZelman
  • SolomonZelman
l - 5 = w + 2 l - 5 = 13 + 2 l = 20 right !!
anonymous
  • anonymous
Thanks so much again!
SolomonZelman
  • SolomonZelman
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.