asib1214
  • asib1214
yelp!!!!!!!!!!!!!!!!!
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Michele_Laino
  • Michele_Laino
here is my reasoning: |dw:1435602585709:dw| the motion of our object is a periodic motion, and its position goes from x=-9 to x=+9 for example: |dw:1435602699924:dw| so we can write: \[\Large 2A = 18\]
Michele_Laino
  • Michele_Laino
A periodic motion, can be described using this function: \[\Large x\left( t \right) = A\cos \left( {\omega t + \varphi } \right)\]
Michele_Laino
  • Michele_Laino
now, since: \[ \Large - 1 \leqslant \cos \left( {\omega t + \varphi } \right) \leqslant 1\] then we have: \[\Large - A \leqslant x\left( t \right) \leqslant A\] and by definition, A is the amplitude of our motion

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Michele_Laino
  • Michele_Laino
ok! Then it is suffice that you write that the total length, namely 18 cm, is twice of our ampliude
Michele_Laino
  • Michele_Laino
amplitude*
Michele_Laino
  • Michele_Laino
your reasoning is right!
Michele_Laino
  • Michele_Laino
yor formula is correct!
Michele_Laino
  • Michele_Laino
your*
Michele_Laino
  • Michele_Laino
Yes! I think so!
Michele_Laino
  • Michele_Laino
thanks! :)
asib1214
  • asib1214
asib1214
  • asib1214
@sweetburger Hey could you please help me with the question up there in pdg.png
asib1214
  • asib1214
I've already done the question could you please check my work???!?!?!!?
Michele_Laino
  • Michele_Laino
the space traveled is 4.8 meters, so the requested velocity is: 4.8/6=0.8 m/sec
asib1214
  • asib1214
sorry this is how i did it. i've given the distance and frequency =3Hz i can figure out the period. f=1/T f= 1/3 f= 0.33sec/cycle From here i can figure out velocity V= Change in distance/change in time 4.8m/0.33sec 14.5m/sec Now that i have the velocity and frequency, i can certainly figure out the the wavelength by rearranging the formula V=D/t 14.5m/sec all over 3 Hz 4.8m
asib1214
  • asib1214
@Michele_Laino can you please check my work?!?!?!!? Thanks man
asib1214
  • asib1214
it's asking me to find the wavelength. Please see the picture i've just uploaded :)
Michele_Laino
  • Michele_Laino
wavelength is: 4.8/3=... since we have three cycles, within 4.8 meters
Michele_Laino
  • Michele_Laino
period T= 6/3 = 2 seconds and frequency f= 1/2 = 0.5 Hz

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