A community for students.
Here's the question you clicked on:
 0 viewing
asib1214
 one year ago
yelp!!!!!!!!!!!!!!!!!
asib1214
 one year ago
yelp!!!!!!!!!!!!!!!!!

This Question is Closed

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here is my reasoning: dw:1435602585709:dw the motion of our object is a periodic motion, and its position goes from x=9 to x=+9 for example: dw:1435602699924:dw so we can write: \[\Large 2A = 18\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1A periodic motion, can be described using this function: \[\Large x\left( t \right) = A\cos \left( {\omega t + \varphi } \right)\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, since: \[ \Large  1 \leqslant \cos \left( {\omega t + \varphi } \right) \leqslant 1\] then we have: \[\Large  A \leqslant x\left( t \right) \leqslant A\] and by definition, A is the amplitude of our motion

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1ok! Then it is suffice that you write that the total length, namely 18 cm, is twice of our ampliude

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1your reasoning is right!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yor formula is correct!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1Yes! I think so!

asib1214
 one year ago
Best ResponseYou've already chosen the best response.1@sweetburger Hey could you please help me with the question up there in pdg.png

asib1214
 one year ago
Best ResponseYou've already chosen the best response.1I've already done the question could you please check my work???!?!?!!?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the space traveled is 4.8 meters, so the requested velocity is: 4.8/6=0.8 m/sec

asib1214
 one year ago
Best ResponseYou've already chosen the best response.1sorry this is how i did it. i've given the distance and frequency =3Hz i can figure out the period. f=1/T f= 1/3 f= 0.33sec/cycle From here i can figure out velocity V= Change in distance/change in time 4.8m/0.33sec 14.5m/sec Now that i have the velocity and frequency, i can certainly figure out the the wavelength by rearranging the formula V=D/t 14.5m/sec all over 3 Hz 4.8m

asib1214
 one year ago
Best ResponseYou've already chosen the best response.1@Michele_Laino can you please check my work?!?!?!!? Thanks man

asib1214
 one year ago
Best ResponseYou've already chosen the best response.1it's asking me to find the wavelength. Please see the picture i've just uploaded :)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1wavelength is: 4.8/3=... since we have three cycles, within 4.8 meters

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1period T= 6/3 = 2 seconds and frequency f= 1/2 = 0.5 Hz
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.