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asib1214

  • one year ago

yelp!!!!!!!!!!!!!!!!!

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  1. Michele_Laino
    • one year ago
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    here is my reasoning: |dw:1435602585709:dw| the motion of our object is a periodic motion, and its position goes from x=-9 to x=+9 for example: |dw:1435602699924:dw| so we can write: \[\Large 2A = 18\]

  2. Michele_Laino
    • one year ago
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    A periodic motion, can be described using this function: \[\Large x\left( t \right) = A\cos \left( {\omega t + \varphi } \right)\]

  3. Michele_Laino
    • one year ago
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    now, since: \[ \Large - 1 \leqslant \cos \left( {\omega t + \varphi } \right) \leqslant 1\] then we have: \[\Large - A \leqslant x\left( t \right) \leqslant A\] and by definition, A is the amplitude of our motion

  4. Michele_Laino
    • one year ago
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    ok! Then it is suffice that you write that the total length, namely 18 cm, is twice of our ampliude

  5. Michele_Laino
    • one year ago
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    amplitude*

  6. Michele_Laino
    • one year ago
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    your reasoning is right!

  7. Michele_Laino
    • one year ago
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    yor formula is correct!

  8. Michele_Laino
    • one year ago
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    your*

  9. Michele_Laino
    • one year ago
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    Yes! I think so!

  10. Michele_Laino
    • one year ago
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    thanks! :)

  11. asib1214
    • one year ago
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  12. asib1214
    • one year ago
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    @sweetburger Hey could you please help me with the question up there in pdg.png

  13. asib1214
    • one year ago
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    I've already done the question could you please check my work???!?!?!!?

  14. Michele_Laino
    • one year ago
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    the space traveled is 4.8 meters, so the requested velocity is: 4.8/6=0.8 m/sec

  15. asib1214
    • one year ago
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    sorry this is how i did it. i've given the distance and frequency =3Hz i can figure out the period. f=1/T f= 1/3 f= 0.33sec/cycle From here i can figure out velocity V= Change in distance/change in time 4.8m/0.33sec 14.5m/sec Now that i have the velocity and frequency, i can certainly figure out the the wavelength by rearranging the formula V=D/t 14.5m/sec all over 3 Hz 4.8m

  16. asib1214
    • one year ago
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    @Michele_Laino can you please check my work?!?!?!!? Thanks man

  17. asib1214
    • one year ago
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    it's asking me to find the wavelength. Please see the picture i've just uploaded :)

  18. Michele_Laino
    • one year ago
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    wavelength is: 4.8/3=... since we have three cycles, within 4.8 meters

  19. Michele_Laino
    • one year ago
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    period T= 6/3 = 2 seconds and frequency f= 1/2 = 0.5 Hz

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