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anonymous
 one year ago
algebraic math problem
If 5a  2b = b + 1 = 9, What is the value of a?
What i'v got so far is
5a 2b = b + 1 = 9
+ 2b + 2b
5a = 3b + 1 = 9
 1  1
5a = 3b = 8
anonymous
 one year ago
algebraic math problem If 5a  2b = b + 1 = 9, What is the value of a? What i'v got so far is 5a 2b = b + 1 = 9 + 2b + 2b 5a = 3b + 1 = 9  1  1 5a = 3b = 8

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Am i doing this right?

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.2This is an application of an axiom, which is also called "trasitive" property. The axiom states that if a number "a" is equal to another number "b" but at the same time "b" is equal to a number "c", then "a" is equal to "c": \[a=b=c\] then: \[a=c\] \[b=c\] That's a summarization of it, but hopefully you get the point. so fo the problem: \[5a2b=b +1=9\] we can view "5a2b" as "a", "b+1" as "b" and "9" as "c", and it resonates with the structure of the trasitive axiom, so we can apply it: \[5a2b=9\] \[b+1=9\] So now you have two equations, where one is univarable, so take the second one, solve for "b" and replace it on the first equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wow I did not know about that property, and sadly i have many to learn on this road however thanks so much! my work was: background as you taught me 5a 2b = a b+1 = b 9 = c meaning two equations i have now 5a2b=9 and b+1=9 and then to solve i took the univariable as suggested and was easier b + 1 = 9 1 1 b = 8 therefore i used b to solve for the second equation 5a  2b = 9 5a  2(8) = 9 5a  16 = 9 +16 +16 5a = 25 5a / 5 = 25 / 5 a = 5 Thank you once again :D
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