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anonymous

  • one year ago

If two 6-sided number cubes are rolled, what is the probability that 6-2 will be rolled?

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  1. anonymous
    • one year ago
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    2 out of 12

  2. perl
    • one year ago
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    I am not sure what you mean by rolling 6-2. Is the question what is the probability of rolling a 4?

  3. anonymous
    • one year ago
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    Assuming a fair die the probability of not rolling a six is 5/6. The probability of not rolling a six on the second roll is also 5/6. As these two events are independent the probability of both occurring, that is no six on either roll, is the two probabilities multiplied together 5/6×5/6=25/36 The probability of getting at least one six is the complement of the probability of getting no sixes 1−25/36=11/36≈30.6 You can extend this analysis to three or more rolls of the die. For three rolls 1−5363=216−125216=91/216≈42.1 which is still less than half. For four rolls we have 1−5464=1296−6251296=671/1296≈51.8 which is finally (just) over half a chance of getting at least one six. Did you know that you are about as likely to not roll a six ten times in a row, as you are to roll a six on the first roll. That is: 1−510610≈83.8 No wonder getting that double to get out of jail in Monopoly sometimes seems to take forever!

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