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Mirandaregina

  • one year ago

How do I find the measure of theta? (image attached)

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  1. Mirandaregina
    • one year ago
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  2. anonymous
    • one year ago
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    look at it like a triangle like this |dw:1435611781411:dw| then use either sin, cos, or tan to solve for theta. Do you know which one to use?

  3. Mirandaregina
    • one year ago
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    @mastermindkakashi no, I don't know which one to use

  4. anonymous
    • one year ago
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    oh well I like to think of SOH CAH TOA to help me figure it out. You would use Tangent to solve for theta since 6 is Opposite and 8 is Adjacent. so in your calculator put in \[\tan \frac{ 6 }{ 8}\]

  5. anonymous
    • one year ago
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    https://www.desmos.com/calculator this is a link to a graphing calculator if you need it

  6. Mirandaregina
    • one year ago
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    @mastermindkakashi I got tan(6/8) = 0.1309 I don't know if my answer is right or not, though, considering the answer choices are A) 41.1 degrees B) 28.3 degrees C) 45 degrees D) 36.8 degrees

  7. anonymous
    • one year ago
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    hm well I got a different answer than you... what do you think it is? I think we can solve it a different way

  8. anonymous
    • one year ago
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    okay so if you look at it by pythagorean theorem, the missing side is 10. so your triangle now looks like this |dw:1435612732862:dw| and you can think of it as a perfect right triangle, which has 45-45-90 angles

  9. Mirandaregina
    • one year ago
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    @mastermindkakashi yeah, I actually got that by solving r = √x^2 + y^2 earlier, I just don't know how to use this info to find theta

  10. anonymous
    • one year ago
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    I think it is 45 degrees because it forms a perfect triangle

  11. Mirandaregina
    • one year ago
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    @mastermindkakashi ahhhh that makes sense! haha thank you for your help!

  12. anonymous
    • one year ago
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    no problem! :D @Mirandaregina

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