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BeccaB003

  • one year ago

Approximate the volume of the regular triangular pyramid if the height is approximately 11.5. (Remember that the base of a regular triangular pyramid must be an equilateral triangle, not necessarily congruent to the sides of the pyramid.) 828 239 717

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  1. BeccaB003
    • one year ago
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    V = 1/3 (base area)(height) V = 1/3 (base area)(12) I need help finding the base area

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  2. taramgrant0543664
    • one year ago
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    Since the base is an equilateral triangle you can solve for the base area by using the formula A=(bxh)/2

  3. BeccaB003
    • one year ago
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    So, A = (12*12)/2 = 72

  4. BeccaB003
    • one year ago
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    V = 1/3 (72)(12) = 288 <------------ But that isn't the correct answer. I got that answer last time I did this problem and it wasn't correct. I was told that I needed to use Hero's formula but I don't know how or why?!

  5. NathalyN
    • one year ago
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    SA: 1/2bh(number of sides) SA: 1/2(12)(12)(4) SA: 1/2(144)(4) SA: 72*4 SA: 288

  6. BeccaB003
    • one year ago
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    That solves for the Surface area not the volume. @NathalyN

  7. BeccaB003
    • one year ago
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    Hero's formula is needed to solve this problem but I don't know how.

  8. BeccaB003
    • one year ago
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    @jim_thompson5910 Can you please help solve this problem?

  9. taramgrant0543664
    • one year ago
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    Here is a link to how to use that formula: https://www.mathsisfun.com/geometry/herons-formula.html I've never heard of this before but I hope it helps

  10. jim_thompson5910
    • one year ago
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    `Remember that the base of a regular triangular pyramid must be an equilateral triangle` the length of the bottom side is 12, so the other 2 sides must also be 12 too plug s = 12 into the area of an equilateral triangle formula \[\Large A = \frac{\sqrt{3}}{4}*s^2\]

  11. BeccaB003
    • one year ago
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    Okay so, \[\frac{ \sqrt{3} }{ 4 }*12^2\] = 62.4

  12. jim_thompson5910
    • one year ago
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    62.3538290724796 which turns into 62.4 if you round to 1 decimal place looks good

  13. jim_thompson5910
    • one year ago
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    that's the area of the base

  14. jim_thompson5910
    • one year ago
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    Volume of pyramid = (1/3)*(area of base)*(height of pyramid)

  15. BeccaB003
    • one year ago
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    So, (1/3) * 62.4 * 12 = 249.6 <--------- that isn't one of the answer options. It is closest to 239. Also, how did you find that formula for an equalateral triangle. Also, can I do this problem using Hero's formula because that is what I was told to use to get the correct answer. @jim_thompson5910

  16. jim_thompson5910
    • one year ago
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    You can use hero's formula, but you'd get the same result if you used the formula I posted above this page shows how the formula is derived http://mathcentral.uregina.ca/QQ/database/QQ.09.03/jared1.html

  17. jim_thompson5910
    • one year ago
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    also why did you use 12 for the height, when the height is 11.5?

  18. BeccaB003
    • one year ago
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    Okay, thank you. Sorry, I didn't mean to use 12. I recalculated it and it and got 239. Thank you so much for your help! :)

  19. BeccaB003
    • one year ago
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    Do you mind helping me with one more problem using the same image? Calculate the surface area of a regular triangular pyramid with the base edges of length 12 and a slant height of 12. (Remember that the base of a regular triangular pyramid must be an equilateral triangle, not necessarily congruent to the sides of the pyramid.)

  20. BeccaB003
    • one year ago
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    SA = Base area + 1/2 bln

  21. BeccaB003
    • one year ago
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    SA = 62.4 + 1/2 (12)(12)(4)

  22. jim_thompson5910
    • one year ago
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    you have one base face and 3 lateral faces

  23. jim_thompson5910
    • one year ago
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    we already have the area of the base face from last time the area of each face is (1/2)*b*h b = base of lateral face triangle = 12 h = height of lateral face triangle = 12

  24. jim_thompson5910
    • one year ago
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    the area of each lateral face is (1/2)*b*h b = base of lateral face triangle = 12 h = height of lateral face triangle = 12

  25. BeccaB003
    • one year ago
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    Wait, I thought it had 4 sides not including the base. It is really hard to tell from the picture... So, it is SA = 62.4 + (1/2)(12)(12)(3)

  26. BeccaB003
    • one year ago
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    So the answer is 278.4?

  27. jim_thompson5910
    • one year ago
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    Rule for a pyramid (any pyramid) there is always one base face (usually on the ground) the lateral faces are triangles and there are n of them where the base is an n-gon (example: n = 4, square pyramid has 4 lateral faces)

  28. jim_thompson5910
    • one year ago
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    yeah approximately

  29. BeccaB003
    • one year ago
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    Okay, so if it doesn't say that it is a square pyramid then it has 3 lateral faces?

  30. jim_thompson5910
    • one year ago
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    the key word "triangular" in "triangular pyramid" means the base is a triangle

  31. jim_thompson5910
    • one year ago
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    if they said "rectangular pyramid", then the base is a rectangle (4 lateral sides)

  32. jim_thompson5910
    • one year ago
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    if they said "pentagonal pyramid" then the base is a pentagon with 5 lateral sides

  33. BeccaB003
    • one year ago
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    Oh! I see. I was really confused because by the picture it looks like there are four lateral sides. Thank you so much for your help! You clear everything up brilliantly! :D

  34. jim_thompson5910
    • one year ago
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    yeah it's hard to convey 3D shapes on a flat 2D page

  35. jim_thompson5910
    • one year ago
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    if you had these (maybe from a kit or something) http://bit-player.org/wp-content/uploads/2012/10/tetrahedron-geomags-06601.jpg then it might be easier to visualize

  36. BeccaB003
    • one year ago
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    I do have something similar to those. Thanks!

  37. jim_thompson5910
    • one year ago
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    no problem

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