## anonymous one year ago The midpoint of (8, 6) and (-2, 12) is (3, 9)?

1. anonymous

True/False

2. geerky42

Midpoint of $$(x_1,y_1)$$ and $$(x_2,y_2)$$ is $$\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$$

3. geerky42

Here, you are given points $$(8,6)$$ and $$(-2,12)$$

4. geerky42

$$x_1 = 8\\~\\x_2 = -2\\~\\y_1 = 6\\~\\y_2 = 12$$ So you have $$\left(\dfrac{8+\text-2}2,\dfrac{6+12}2\right)\quad\Longrightarrow\quad ?$$

5. anonymous

its false

6. anonymous

thank you

7. geerky42

8. anonymous

just look on a graph

9. geerky42

I think you should take a second look at graph.