## anonymous one year ago Solve the following system of equations and show all work. y = 2x^2 y = –3x −1

1. taramgrant0543664

To start you have to put them equal to each other then you have to get everything to the one side so one side has everything and the other side is equal to zero

2. anonymous

so 2x^2=-3x-1 ? @taramgrant0543664

3. taramgrant0543664

yes that is the first step! so now the next step is to get it all on to one side (I suggest that you move the stuff on the right to the left side so you don't have to deal with the negatives)

4. anonymous

2x^2+3x+1=0 ? @taramgrant0543664

5. taramgrant0543664

Perfect! So now the next step that we are going to do is put it into the quadratic formula: a will represent the the number in front of the x^2 in this case 2 b will represent the number in front the x in this case 3 and c will represent the last number in this case 1$(-b \pm \sqrt{b ^{2}-4ac})\div2a$

6. taramgrant0543664

You will get two numbers one when using the + and one when using the - from the +/-

7. anonymous

-1/2 and -1 ?? @taramgrant0543664

8. taramgrant0543664

Yep that's what I got!

9. anonymous

cool thanks , can you help with more ?