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anonymous

  • one year ago

will fan and medal

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  1. anonymous
    • one year ago
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    Using the completing-the-square method, rewrite f(x) = x2 − 8x + 3 in vertex form. f(x) = (x − 8)2 f(x) = (x − 4)2 − 13 f(x) = (x − 4)2 + 3 f(x) = (x − 4)2 + 16

  2. anonymous
    • one year ago
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    @dan815

  3. anonymous
    • one year ago
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    @jim_thompson5910 plz help

  4. anonymous
    • one year ago
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    i think B

  5. anonymous
    • one year ago
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    how did you get it

  6. anonymous
    • one year ago
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    do you think its b ?

  7. jim_thompson5910
    • one year ago
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    |dw:1435621592774:dw|

  8. jim_thompson5910
    • one year ago
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    |dw:1435621614093:dw|

  9. jim_thompson5910
    • one year ago
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    |dw:1435621632111:dw|

  10. jim_thompson5910
    • one year ago
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    use the formula h = -b/(2a) to find h. Tell me what you get

  11. anonymous
    • one year ago
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    i have no clue how to do this

  12. anonymous
    • one year ago
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    i just want someone to help me figure it out

  13. jim_thompson5910
    • one year ago
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    do you see how I got b = -8 and a = 1 ??

  14. anonymous
    • one year ago
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    yes

  15. jim_thompson5910
    • one year ago
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    plug those values into the formula h = -b/(2*a)

  16. anonymous
    • one year ago
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    a = 1 b = -1 c = 2 ?????

  17. jim_thompson5910
    • one year ago
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    h = -b/(2*a) h = -(-8)/(2*1) h = 4 making sense?

  18. anonymous
    • one year ago
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    ooooohhhhhhh, let me explain real quick

  19. anonymous
    • one year ago
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    so h = -b/(2*a) is the formula and all i have to do is plug in the numbers ?!?!?!

  20. jim_thompson5910
    • one year ago
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    yeah plug in a = 1 and b = -8

  21. anonymous
    • one year ago
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    for some reason i read it wrong

  22. anonymous
    • one year ago
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    so now what?

  23. jim_thompson5910
    • one year ago
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    h = 4, plug this into x of the original equation to find y

  24. anonymous
    • one year ago
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    f(x) = x2 − 8x + 3 h = -b/(2*a) x= - 8/6 ????

  25. anonymous
    • one year ago
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    am i close

  26. jim_thompson5910
    • one year ago
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    replace every x in the original equation with 4 then compute

  27. jim_thompson5910
    • one year ago
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    not really

  28. anonymous
    • one year ago
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    lol

  29. anonymous
    • one year ago
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    f(x) = 8 − 32 + 3

  30. jim_thompson5910
    • one year ago
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    |dw:1435622365786:dw|

  31. jim_thompson5910
    • one year ago
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    |dw:1435622392834:dw|

  32. jim_thompson5910
    • one year ago
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    use PEMDAS or a calculator to compute

  33. anonymous
    • one year ago
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    i sorry, i suck at math

  34. jim_thompson5910
    • one year ago
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    use a calculator if needed

  35. jim_thompson5910
    • one year ago
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    free calculator http://web2.0calc.com/

  36. jim_thompson5910
    • one year ago
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    |dw:1435622494155:dw|

  37. jim_thompson5910
    • one year ago
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    |dw:1435622519411:dw|

  38. anonymous
    • one year ago
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    -13

  39. jim_thompson5910
    • one year ago
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    so that is the value of k

  40. jim_thompson5910
    • one year ago
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    h = 4 k = -13

  41. jim_thompson5910
    • one year ago
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    plug a = 1 h = 4 k = -13 into \[\Large f(x) = a(x-h)^2 + k\]

  42. anonymous
    • one year ago
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    f(x)=1(x-4)^2+1-13

  43. anonymous
    • one year ago
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    -13*

  44. jim_thompson5910
    • one year ago
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    yeah (x-4)^2 - 13

  45. anonymous
    • one year ago
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    i don't see that option

  46. anonymous
    • one year ago
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    never mind

  47. anonymous
    • one year ago
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    thank you for your time and patience

  48. anonymous
    • one year ago
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    <3<3<3

  49. jim_thompson5910
    • one year ago
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    no problem

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