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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Using the completingthesquare method, rewrite f(x) = x2 − 8x + 3 in vertex form. f(x) = (x − 8)2 f(x) = (x − 4)2 − 13 f(x) = (x − 4)2 + 3 f(x) = (x − 4)2 + 16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 plz help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you think its b ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435621592774:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435621614093:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435621632111:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1use the formula h = b/(2a) to find h. Tell me what you get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have no clue how to do this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just want someone to help me figure it out

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1do you see how I got b = 8 and a = 1 ??

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1plug those values into the formula h = b/(2*a)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a = 1 b = 1 c = 2 ?????

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1h = b/(2*a) h = (8)/(2*1) h = 4 making sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ooooohhhhhhh, let me explain real quick

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so h = b/(2*a) is the formula and all i have to do is plug in the numbers ?!?!?!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah plug in a = 1 and b = 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for some reason i read it wrong

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1h = 4, plug this into x of the original equation to find y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x) = x2 − 8x + 3 h = b/(2*a) x=  8/6 ????

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1replace every x in the original equation with 4 then compute

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435622365786:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435622392834:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1use PEMDAS or a calculator to compute

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i sorry, i suck at math

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1use a calculator if needed

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1free calculator http://web2.0calc.com/

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435622494155:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435622519411:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so that is the value of k

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1h = 4 k = 13

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1plug a = 1 h = 4 k = 13 into \[\Large f(x) = a(xh)^2 + k\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah (x4)^2  13

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't see that option

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you for your time and patience
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