anonymous
  • anonymous
will fan and medal
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Using the completing-the-square method, rewrite f(x) = x2 − 8x + 3 in vertex form. f(x) = (x − 8)2 f(x) = (x − 4)2 − 13 f(x) = (x − 4)2 + 3 f(x) = (x − 4)2 + 16
anonymous
  • anonymous
anonymous
  • anonymous

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anonymous
  • anonymous
i think B
anonymous
  • anonymous
how did you get it
anonymous
  • anonymous
do you think its b ?
jim_thompson5910
  • jim_thompson5910
|dw:1435621592774:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435621614093:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435621632111:dw|
jim_thompson5910
  • jim_thompson5910
use the formula h = -b/(2a) to find h. Tell me what you get
anonymous
  • anonymous
i have no clue how to do this
anonymous
  • anonymous
i just want someone to help me figure it out
jim_thompson5910
  • jim_thompson5910
do you see how I got b = -8 and a = 1 ??
anonymous
  • anonymous
yes
jim_thompson5910
  • jim_thompson5910
plug those values into the formula h = -b/(2*a)
anonymous
  • anonymous
a = 1 b = -1 c = 2 ?????
jim_thompson5910
  • jim_thompson5910
h = -b/(2*a) h = -(-8)/(2*1) h = 4 making sense?
anonymous
  • anonymous
ooooohhhhhhh, let me explain real quick
anonymous
  • anonymous
so h = -b/(2*a) is the formula and all i have to do is plug in the numbers ?!?!?!
jim_thompson5910
  • jim_thompson5910
yeah plug in a = 1 and b = -8
anonymous
  • anonymous
for some reason i read it wrong
anonymous
  • anonymous
so now what?
jim_thompson5910
  • jim_thompson5910
h = 4, plug this into x of the original equation to find y
anonymous
  • anonymous
f(x) = x2 − 8x + 3 h = -b/(2*a) x= - 8/6 ????
anonymous
  • anonymous
am i close
jim_thompson5910
  • jim_thompson5910
replace every x in the original equation with 4 then compute
jim_thompson5910
  • jim_thompson5910
not really
anonymous
  • anonymous
lol
anonymous
  • anonymous
f(x) = 8 − 32 + 3
jim_thompson5910
  • jim_thompson5910
|dw:1435622365786:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435622392834:dw|
jim_thompson5910
  • jim_thompson5910
use PEMDAS or a calculator to compute
anonymous
  • anonymous
i sorry, i suck at math
jim_thompson5910
  • jim_thompson5910
use a calculator if needed
jim_thompson5910
  • jim_thompson5910
free calculator http://web2.0calc.com/
jim_thompson5910
  • jim_thompson5910
|dw:1435622494155:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1435622519411:dw|
anonymous
  • anonymous
-13
jim_thompson5910
  • jim_thompson5910
so that is the value of k
jim_thompson5910
  • jim_thompson5910
h = 4 k = -13
jim_thompson5910
  • jim_thompson5910
plug a = 1 h = 4 k = -13 into \[\Large f(x) = a(x-h)^2 + k\]
anonymous
  • anonymous
f(x)=1(x-4)^2+1-13
anonymous
  • anonymous
-13*
jim_thompson5910
  • jim_thompson5910
yeah (x-4)^2 - 13
anonymous
  • anonymous
i don't see that option
anonymous
  • anonymous
never mind
anonymous
  • anonymous
thank you for your time and patience
anonymous
  • anonymous
<3<3<3
jim_thompson5910
  • jim_thompson5910
no problem

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