mckenzieandjesus
  • mckenzieandjesus
What is the standard form of the equation of the circle in the graph? (x - 1)2 + (y - 2)2 = 16 (x - 1)2 + (y - 2)2 = 4 (x + 1)2 + (y + 2)2 = 16 (x + 1)2 + (y + 2)2 = 4
Geometry
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SOLVED
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schrodinger
  • schrodinger
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mckenzieandjesus
  • mckenzieandjesus
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mckenzieandjesus
  • mckenzieandjesus
@jim_thompson5910
mckenzieandjesus
  • mckenzieandjesus
I think it is answer D

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jim_thompson5910
  • jim_thompson5910
why D?
jim_thompson5910
  • jim_thompson5910
what's your thinking on it
mckenzieandjesus
  • mckenzieandjesus
because i thought that its positive 1 and 2 up
mckenzieandjesus
  • mckenzieandjesus
but i forget how to do this so i wasnt sure
jim_thompson5910
  • jim_thompson5910
this is a common mistake, the signs actually are flipped
jim_thompson5910
  • jim_thompson5910
since you have (x-h) and (y-k)
mckenzieandjesus
  • mckenzieandjesus
ohh
jim_thompson5910
  • jim_thompson5910
http://www.regentsprep.org/regents/math/algtrig/atc1/circlelesson.htm
mckenzieandjesus
  • mckenzieandjesus
so then would it be B?
jim_thompson5910
  • jim_thompson5910
what is the radius here
mckenzieandjesus
  • mckenzieandjesus
(1, 2)?
mckenzieandjesus
  • mckenzieandjesus
or 2?
jim_thompson5910
  • jim_thompson5910
it's the distance from center to edge of the circle
mckenzieandjesus
  • mckenzieandjesus
5
jim_thompson5910
  • jim_thompson5910
you miscounted
mckenzieandjesus
  • mckenzieandjesus
i know its 4 because 1^2*2^2= 4
mckenzieandjesus
  • mckenzieandjesus
oh then 4
jim_thompson5910
  • jim_thompson5910
r = 4 so r^2 = 16
jim_thompson5910
  • jim_thompson5910
in that link they have r^2 on the right side not just r
mckenzieandjesus
  • mckenzieandjesus
ohh
mckenzieandjesus
  • mckenzieandjesus
its A then right?
jim_thompson5910
  • jim_thompson5910
yes

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