What is the standard form of the equation of the circle in the graph? (x - 1)2 + (y - 2)2 = 16 (x - 1)2 + (y - 2)2 = 4 (x + 1)2 + (y + 2)2 = 16 (x + 1)2 + (y + 2)2 = 4

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What is the standard form of the equation of the circle in the graph? (x - 1)2 + (y - 2)2 = 16 (x - 1)2 + (y - 2)2 = 4 (x + 1)2 + (y + 2)2 = 16 (x + 1)2 + (y + 2)2 = 4

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I think it is answer D

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Other answers:

why D?
what's your thinking on it
because i thought that its positive 1 and 2 up
but i forget how to do this so i wasnt sure
this is a common mistake, the signs actually are flipped
since you have (x-h) and (y-k)
ohh
http://www.regentsprep.org/regents/math/algtrig/atc1/circlelesson.htm
so then would it be B?
what is the radius here
(1, 2)?
or 2?
it's the distance from center to edge of the circle
5
you miscounted
i know its 4 because 1^2*2^2= 4
oh then 4
r = 4 so r^2 = 16
in that link they have r^2 on the right side not just r
ohh
its A then right?
yes

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