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anonymous
 one year ago
Tabitha is trying to find the equation of a line perpendicular to y = 1 over 2x − 5 in slopeintercept form that passes through the point (2, −7). Which of the following equations will she use?
anonymous
 one year ago
Tabitha is trying to find the equation of a line perpendicular to y = 1 over 2x − 5 in slopeintercept form that passes through the point (2, −7). Which of the following equations will she use?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a) y − (−7) = 1 over 2(x − 2) b) y − 2 = 1 over 2(x − (−7)) c) y − (−7) = −2(x − 2) d) y − 2 = −2(x − (−7))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you been at this one for a while huh?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes! can't seem to figure it out :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok lets go slow (but not that slow) the slope of \[y=\color{red}{\frac{1}{2}}x5\] is ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right and the perpendicular line with have a slope that is the "negative reciprocal" i.e. flip it and change the sign

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right, which, on planet earth, we usually just call \(2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now we got the slope the point is \((2,7)\) and they want you to plug all this in to the "point  slope" formula \[yy_1=m(xx_1)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where you see \(y_1\) put \(7\) where you see \(m\) put \(2\) and where you see \(x_1\) put \(2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, it is always C how hard was that? ok?
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