anonymous
  • anonymous
Can you solve this? There are four girls and 2 boys in a study group on a test (with each problem worth the same value), each of the 6 students solved a different number of problems. The highest-scoring student solving 10 problems and the lowest-scoring student solving 4 problems. The highest scoring girl solved 4 more problems than the lowest-scoring boy The highest scoring boy solved 4 more problems than the lowest-scoring girl QUESTION: How many problems did the highest scoring boy solve?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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mathstudent55
  • mathstudent55
|dw:1435632689410:dw|
mathstudent55
  • mathstudent55
The girls are listed from G1 to G4 with G1 being the highest scoring girl to G4 being the lowest scoring girl. The same is done with the boys, B1 scored higher than B2
mathstudent55
  • mathstudent55
|dw:1435632840162:dw|

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mathstudent55
  • mathstudent55
Now we know the highest scoring student scored 10. Let's first assume that the highest scoring student is the highest scoring girl.
mathstudent55
  • mathstudent55
|dw:1435632978843:dw|
mathstudent55
  • mathstudent55
Since the lowest scoring by has 6, and the lowest score of all is 4, that must be a girl.
mathstudent55
  • mathstudent55
That makes the higher scoring boy score an 8. |dw:1435633064742:dw|
mathstudent55
  • mathstudent55
Now we need to make the other assumption.
mathstudent55
  • mathstudent55
Let's assume it's the higher scoring boy who got the 10.
mathstudent55
  • mathstudent55
|dw:1435633167570:dw|
mathstudent55
  • mathstudent55
With this assumption, we have the lowest girl score is 6 and the highest is 8. There are only 3 scores the girls could have had, 6, 7, and 8. There are 4 girls. That means two must have had the same score, but we were told each student had a different score, so this second assumption is incorrect. The first assumption is correct, and the higher boys' score is 8.
anonymous
  • anonymous
Wow! I get it now. Thank you so much @mathstudent55 for answering my question.

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