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anonymous

  • one year ago

The next three batters on a baseball team have hit percentages of 0.325, 0.250, and 0.275, respectively. What is the probability that the first and third batters will both get a hit, while the second batter does not?

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  1. anonymous
    • one year ago
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    multiply

  2. anonymous
    • one year ago
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    actually first compute the probability that the second batter does not get a hit, which is \(1-.25\) then multiply

  3. anonymous
    • one year ago
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    I'll add that the possible answers are A. 0.067 B. 0.201 C. 0.217 D. 0.603

  4. anonymous
    • one year ago
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    and ill try that

  5. anonymous
    • one year ago
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    \(1-.25=.75\) multiply \[0.325\times 0.75\times 0.275\] it should be a pretty small number

  6. anonymous
    • one year ago
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    0.067ish? that sounds about right

  7. anonymous
    • one year ago
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    looks good to me

  8. anonymous
    • one year ago
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    Thanks!

  9. anonymous
    • one year ago
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    yw

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