anonymous
  • anonymous
The next three batters on a baseball team have hit percentages of 0.325, 0.250, and 0.275, respectively. What is the probability that the first and third batters will both get a hit, while the second batter does not?
Meta-math
chestercat
  • chestercat
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anonymous
  • anonymous
multiply
anonymous
  • anonymous
actually first compute the probability that the second batter does not get a hit, which is \(1-.25\) then multiply
anonymous
  • anonymous
I'll add that the possible answers are A. 0.067 B. 0.201 C. 0.217 D. 0.603

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anonymous
  • anonymous
and ill try that
anonymous
  • anonymous
\(1-.25=.75\) multiply \[0.325\times 0.75\times 0.275\] it should be a pretty small number
anonymous
  • anonymous
0.067ish? that sounds about right
anonymous
  • anonymous
looks good to me
anonymous
  • anonymous
Thanks!
anonymous
  • anonymous
yw

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