The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. Find the measure of the smaller angle. 18° 36° 54° 58°

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The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. Find the measure of the smaller angle. 18° 36° 54° 58°

Mathematics
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Angle: x Complement: 90 - x
Sum of the complements: x + 90 - x = 90
2x??

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Other answers:

Difference of their measures: x - (90 - x)
90 exceeds x - (90 - x) by 72 That means: 90 - [x - (90 - x)] = 72
Solve for x.
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i distribute the negitive?
If x is more than 45, then subtract x from 90
so it would be a
A
90 - [x - (90 - x)] = 72 90 - [x - 90 + x] = 72 90 - [2x - 90] = 72 90 - 2x + 90 = 72 -2x + 180 = 72 -2x = -108 x = 54 The measure of one of the angles is 54. Since complementary angles add to 90, the other angle is 90 - x. 90 - 54 = 36 Since they ask fot eh measure of the smaller angle, the answer is 36.
thank you man that much simpler
^the last sentence above should read: Since they ask for the measure of the smaller angle, the answer is 36.
You're welcome.

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