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anonymous
 one year ago
evaluate the radical expression and express the result in a+bi form
anonymous
 one year ago
evaluate the radical expression and express the result in a+bi form

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(3\sqrt{5}) (1+\sqrt{1})\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1well you need to distribute so it is \[3(1 + \sqrt{1})\sqrt{5}(1 + \sqrt{1})\] what do you think the next line of working is..?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[3(1+i)i \sqrt{5}(1+i)\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0good, now distribute the 3, and the i√5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(3+3i)(i \sqrt{5}+1\sqrt{5}) ?\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[(3\sqrt{5}) (1+\sqrt{1}) \] \[(3\sqrt{5}i) (1+i)\] now expand.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0all negatives in the radical should be pulled out first.. so that square root of 5 should be square root of 5 i

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0\[3(1+i)i \sqrt{5}(1+i)\\=(3+3i)+(i \sqrt{5}\sqrt{5}i\times i) \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[(3\sqrt{5}i) (1+i) \] \[3+3i\sqrt{5}i\sqrt{5}(i)(i)\] note \[i^2 = 1 \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0typed too fast... 1 inside the square root is just an i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(3+\sqrt{5})+(3\sqrt{5})i\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[3+3i\sqrt{5}i\sqrt{5}(1)\] \[3+3i\sqrt{5}i+\sqrt{5}\] \[3+\sqrt{5}+3i\sqrt{5}i\] \[\[3+\sqrt{5}+i(3\sqrt{5})\]\] yeah it's correct

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0my i is placed differently, but it shouldn't matter because we still have a+bi only our a =\[3+\sqrt{5}\] and b = \[3\sqrt{5}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0it's best to convert all negatives in the square root to i's first and if it's a perfect square like \[\sqrt{1} \] just take the square root and add an i \[\sqrt{1} \rightarrow i \] similarly for \[\sqrt{5} \rightarrow \sqrt{5}i\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0but 5 isn't a perfect square so leave it in the radical and only the negative pops out of the radical and becomes i

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0negatives inside the radical produce imaginary results.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0then use foil and i^2 = 1 ... simplify until a+bi or ai+b form is achieved.
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