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anonymous
 one year ago
Corinne and Aretha are having a 26mile race. Corinne gave Aretha a head start by letting her begin 3.5 miles in front of the start line. Their distances past the start line as the race has progressed can be represented by linear functions and are shown in the table and graph below. How many minutes after the start of the race will Corinne catch Aretha?
anonymous
 one year ago
Corinne and Aretha are having a 26mile race. Corinne gave Aretha a head start by letting her begin 3.5 miles in front of the start line. Their distances past the start line as the race has progressed can be represented by linear functions and are shown in the table and graph below. How many minutes after the start of the race will Corinne catch Aretha?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No table and graph shown.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Corinne’s Distance Past the Start Line Time (minutes) 10 20 30 40 50 Distance (miles) 1.25 2.5 3.75 5.0 6.25 mc0261.jpg 140 minutes 180 minutes 208 minutes 225 minutes

TrojanPoem
 one year ago
Best ResponseYou've already chosen the best response.0May you clarify a bit ? Time (minutes) for corinee 10 20 30 40 50 mc0261.jpg 140 minutes 180 minutes 208 minutes 225 minutes for who ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So first thing is to draw up a graph dw:1435460554181:dw where is Aretha's values?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0With respect, I dont know Aretha's times. You state in the question these are given, but you have only shown corrie's so far.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0graph both lines and find the intersection of the two lines

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's simple as that. Enter the values with certain intervals and wherever one intersects the other is where the first starter is being passed by the second

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright Idk how this openstudy wrk but I just want the answrs and give out medals

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mariemetayer96 there is so much we can do with the data we are given. If we are not given all the values we cant complete the question. As @Robert136 has suggested, you need to graph both of the girls distances, I could graph the first one, becuase you gave me the values for Corrie, but you didnt give me the values for Aretha. So, without the values, it is not possible to draw the second linear function.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now you are talking! give me a minute!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Keep extending the lines broo

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0punch them in on excel

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Robert136 how's that!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so you can see where the two graphs intersect now. at approximately (110,14) which means that Corrie will catch Aretha after approx 100 minutes.(since they both start at 10 minutes and meet each other at 110)
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