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anonymous
 one year ago
help! fan and medal!
a ball is thrown vertically upward from the top of a 100foot tower, with an initial velocity of 20ft/sec. its position function is s(t)=16t^2+20t+100. what is its velocity in ft/sec when t=1 second?
a. 12
b.44
c.100
d.32
what is the average rate of change of y with respect to x over the interval [2,5] for the function y=3+2?
a. 9
b.3
c.1/3 ( wrong answer )
d.1
anonymous
 one year ago
help! fan and medal! a ball is thrown vertically upward from the top of a 100foot tower, with an initial velocity of 20ft/sec. its position function is s(t)=16t^2+20t+100. what is its velocity in ft/sec when t=1 second? a. 12 b.44 c.100 d.32 what is the average rate of change of y with respect to x over the interval [2,5] for the function y=3+2? a. 9 b.3 c.1/3 ( wrong answer ) d.1

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1What's stopping you from plugging t = 1 for the first problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im getting a choice that is not presented. I don't know what im doing wrong see: 16(1)^2+20(1)+100 I get 104

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Oh I see, you want the velocity, what you have there is the position, take the derivative and plug t = 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what would be the derivative?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Have you done calculus?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am taking the class. lol I am stuck on this lesson. what would be the answer to my questions ?would you be able to work the problems out and show me how to do it. im confused.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[s'(t) = 32t20\] would be your velocity

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1First derivative of displacement is velocity, the second is acceleration.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where are you he 32 from o.o

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Mhm, I just used the power rule

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ d }{ dx } x^n = nx^{n1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0more confused lol. ok show me how to solve this. o.o

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok it seems you haven't got far at all in calculus yet lol

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok, so can you tell me what you know?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pretty much what I first posted while trying to find an answer to my questions lol. I have limited time so im fussing over what I am doing wrong lol. o.) here is my guess: 1 44 2 9 am I right?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You can use other methods such as the kinematic equations I suppose, but this question requires you to understand calculus, I gave you the derivative already, so you should be able to figure it out :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what I am getting now for my first answer is 32. did I do that right?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No, the derivative is s'(t) = 32t20, so you still have to plug in t=1 in this equation.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1And for your second question average rate of change is \[\frac{ f(b)f(a) }{ ba }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok I plugged t=1 in and got 52. not one of my choices.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1How did you get that?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[s(t) = 16t^2+20t+100,~~~s'(t) = 32t+20\] plug t = 1, into s'(t), so find s'(1).

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Like I said s(t) is your position, but s'(t) is your velocity

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1And you're looking for velocity when t = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01=32(1)+20 1= 32+20 1=12 then what? t=12?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Well you leave s'(1) alone, but yes,  12.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I said 12 earlier lol

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You said 32 and 52

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1But do you understand how that is?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You will need to read your book/ youtube videos I think, then you will really understand it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. thanks. um on the second question a would be 2 and b is 5. right?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1y=2+3? That's just a horizontal line

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1is there suppose to be an x there somewhere haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y=3x+2 im supposed to look for the average rate of y with respect to x over the interval [2,5] for the function y=3x+2. so this is basically like my slope formula? m=y2y1/x2x1?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ f(5)f(2) }{ 5(2) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0making my answer for number 2 , 1? lol

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1If it makes more sense, y = 3x+2 just means f(x) = 3x+2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You should not get 1

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That sounds good!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0quicl question. lol would this answer of mine be correct: what is the slope for the function y=5x^2+2 at the point x=1? a 5 ( my choice) b 10 c3 ( not the answer) dslope no determined

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1How did you get it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I went with this: y=mx+b formula looked at the slope of my equation which is 5. is my reasoning wrong?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No, all these problems require calculus

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You need to use \[\lim_{h \rightarrow 0} \frac{ f(a+h)f(a) }{ h }\] use this definition to find it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1It's not a linear equation it's y = 5x^2+2, if it was y = 5x+2 we could say slope is 5.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would is et it up though?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{h \rightarrow 0} \frac{ f(1+h)f(1) }{ h }\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Can you do the rest?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im assuming h is 0? making my anser =cannot be determined?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No, limit h > 0 does not mean h = 0, you need to simplify the problem, before you start taking the limit.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Hey, why are they giving you these problems if you haven't learnt it yet..?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know im in a pickle?. lol ok then is it 10?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1If you show your work I will tell you whether you're right or not, use the draw tool if you want to, because otherwise to me it seems you're just guessing.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in this question I am lol if h does not equal 0 its just approaching 0? how would I be able to find h before solving o.o

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Use your equation you are given, plug it into the "formula" I gave you \[\lim_{h \rightarrow 0} \frac{ 5(1+h)^2+2(5(1)^2+2 )}{ h }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03? I put that previously a

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Oh, I don't know.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Well since you're out of time I guess I will show you how to do it, the answer I got was 5. @magy33

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1435652296303:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Note that we keep the limit till we actually take the limit itself.
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