anonymous
  • anonymous
help! fan and medal! a ball is thrown vertically upward from the top of a 100-foot tower, with an initial velocity of 20ft/sec. its position function is s(t)=-16t^2+20t+100. what is its velocity in ft/sec when t=1 second? a. -12 b.-44 c.100 d.-32 what is the average rate of change of y with respect to x over the interval [-2,5] for the function y=3+2? a. -9 b.3 c.1/3 ( wrong answer ) d.-1
Calculus1
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Astrophysics
  • Astrophysics
What's stopping you from plugging t = 1 for the first problem?
anonymous
  • anonymous
im getting a choice that is not presented. I don't know what im doing wrong see: -16(1)^2+20(1)+100 I get 104
Astrophysics
  • Astrophysics
Oh I see, you want the velocity, what you have there is the position, take the derivative and plug t = 1.

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anonymous
  • anonymous
what would be the derivative?
Astrophysics
  • Astrophysics
Have you done calculus?
anonymous
  • anonymous
I am taking the class. lol I am stuck on this lesson. what would be the answer to my questions ?would you be able to work the problems out and show me how to do it. im confused.
Astrophysics
  • Astrophysics
\[s'(t) = -32t-20\] would be your velocity
Astrophysics
  • Astrophysics
First derivative of displacement is velocity, the second is acceleration.
anonymous
  • anonymous
where are you he 32 from o.o
Astrophysics
  • Astrophysics
Mhm, I just used the power rule
Astrophysics
  • Astrophysics
\[\frac{ d }{ dx } x^n = nx^{n-1}\]
anonymous
  • anonymous
more confused lol. ok show me how to solve this. o.o
Astrophysics
  • Astrophysics
Ok it seems you haven't got far at all in calculus yet lol
anonymous
  • anonymous
yup
Astrophysics
  • Astrophysics
Ok, so can you tell me what you know?
anonymous
  • anonymous
pretty much what I first posted while trying to find an answer to my questions lol. I have limited time so im fussing over what I am doing wrong lol. o.) here is my guess: 1- -44 2- -9 am I right?
Astrophysics
  • Astrophysics
You can use other methods such as the kinematic equations I suppose, but this question requires you to understand calculus, I gave you the derivative already, so you should be able to figure it out :)
anonymous
  • anonymous
so what I am getting now for my first answer is -32. did I do that right?
Astrophysics
  • Astrophysics
No, the derivative is s'(t) = -32t-20, so you still have to plug in t=1 in this equation.
Astrophysics
  • Astrophysics
And for your second question average rate of change is \[\frac{ f(b)-f(a) }{ b-a }\]
anonymous
  • anonymous
ok I plugged t=1 in and got -52. not one of my choices.
Astrophysics
  • Astrophysics
How did you get that?
Astrophysics
  • Astrophysics
\[s(t) = -16t^2+20t+100,~~~s'(t) = -32t+20\] plug t = 1, into s'(t), so find s'(1).
Astrophysics
  • Astrophysics
Like I said s(t) is your position, but s'(t) is your velocity
Astrophysics
  • Astrophysics
And you're looking for velocity when t = 1
anonymous
  • anonymous
1=-32(1)+20 1= -32+20 1=-12 then what? t=-12?
Astrophysics
  • Astrophysics
Well you leave s'(1) alone, but yes, - 12.
anonymous
  • anonymous
I said -12 earlier lol
Astrophysics
  • Astrophysics
You said -32 and -52
Astrophysics
  • Astrophysics
But do you understand how that is?
Astrophysics
  • Astrophysics
You will need to read your book/ youtube videos I think, then you will really understand it.
anonymous
  • anonymous
yes. thanks. um on the second question a would be -2 and b is 5. right?
Astrophysics
  • Astrophysics
Yup
Astrophysics
  • Astrophysics
a = -2, b = 5
Astrophysics
  • Astrophysics
y=2+3? That's just a horizontal line
Astrophysics
  • Astrophysics
is there suppose to be an x there somewhere haha
anonymous
  • anonymous
y=3x+2 im supposed to look for the average rate of y with respect to x over the interval [-2,5] for the function y=3x+2. so this is basically like my slope formula? m=y2-y1/x2-x1?
Astrophysics
  • Astrophysics
Yes, similarly
Astrophysics
  • Astrophysics
\[\frac{ f(5)-f(-2) }{ 5-(-2) }\]
anonymous
  • anonymous
making my answer for number 2 , --1? lol
Astrophysics
  • Astrophysics
Show your work
Astrophysics
  • Astrophysics
If it makes more sense, y = 3x+2 just means f(x) = 3x+2
Astrophysics
  • Astrophysics
You should not get -1
anonymous
  • anonymous
I got 3
Astrophysics
  • Astrophysics
That sounds good!
anonymous
  • anonymous
quicl question. lol would this answer of mine be correct: what is the slope for the function y=-5x^2+2 at the point x=1? a- -5 ( my choice) b- -10 c--3 ( not the answer) d-slope no determined
Astrophysics
  • Astrophysics
How did you get it
anonymous
  • anonymous
I went with this: y=mx+b formula looked at the slope of my equation which is -5. is my reasoning wrong?
Astrophysics
  • Astrophysics
No, all these problems require calculus
Astrophysics
  • Astrophysics
You need to use \[\lim_{h \rightarrow 0} \frac{ f(a+h)-f(a) }{ h }\] use this definition to find it
Astrophysics
  • Astrophysics
It's not a linear equation it's y = -5x^2+2, if it was y = -5x+2 we could say slope is -5.
anonymous
  • anonymous
how would is et it up though?
Astrophysics
  • Astrophysics
\[\lim_{h \rightarrow 0} \frac{ f(1+h)-f(1) }{ h }\]
Astrophysics
  • Astrophysics
Can you do the rest?
anonymous
  • anonymous
im assuming h is 0? making my anser =cannot be determined?
Astrophysics
  • Astrophysics
No, limit h -> 0 does not mean h = 0, you need to simplify the problem, before you start taking the limit.
Astrophysics
  • Astrophysics
Hey, why are they giving you these problems if you haven't learnt it yet..?
anonymous
  • anonymous
I don't know im in a pickle?. lol ok then is it -10?
Astrophysics
  • Astrophysics
If you show your work I will tell you whether you're right or not, use the draw tool if you want to, because otherwise to me it seems you're just guessing.
anonymous
  • anonymous
in this question I am lol if h does not equal 0 its just approaching 0? how would I be able to find h before solving o.o
Astrophysics
  • Astrophysics
Use your equation you are given, plug it into the "formula" I gave you \[\lim_{h \rightarrow 0} \frac{ -5(1+h)^2+2-(-5(1)^2+2 )}{ h }\]
Astrophysics
  • Astrophysics
Now simplify
anonymous
  • anonymous
-3? I put that previously a
Astrophysics
  • Astrophysics
Oh, I don't know.
Astrophysics
  • Astrophysics
Well since you're out of time I guess I will show you how to do it, the answer I got was -5. @magy33
Astrophysics
  • Astrophysics
|dw:1435652296303:dw|
Astrophysics
  • Astrophysics
Note that we keep the limit till we actually take the limit itself.

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