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What's stopping you from plugging t = 1 for the first problem?

what would be the derivative?

Have you done calculus?

\[s'(t) = -32t-20\] would be your velocity

First derivative of displacement is velocity, the second is acceleration.

where are you he 32 from o.o

Mhm, I just used the power rule

\[\frac{ d }{ dx } x^n = nx^{n-1}\]

more confused lol. ok show me how to solve this. o.o

Ok it seems you haven't got far at all in calculus yet lol

yup

Ok, so can you tell me what you know?

so what I am getting now for my first answer is -32. did I do that right?

No, the derivative is s'(t) = -32t-20, so you still have to plug in t=1 in this equation.

And for your second question average rate of change is \[\frac{ f(b)-f(a) }{ b-a }\]

ok I plugged t=1 in and got -52. not one of my choices.

How did you get that?

\[s(t) = -16t^2+20t+100,~~~s'(t) = -32t+20\] plug t = 1, into s'(t), so find s'(1).

Like I said s(t) is your position, but s'(t) is your velocity

And you're looking for velocity when t = 1

1=-32(1)+20
1= -32+20
1=-12
then what?
t=-12?

Well you leave s'(1) alone, but yes, - 12.

I said -12 earlier lol

You said -32 and -52

But do you understand how that is?

You will need to read your book/ youtube videos I think, then you will really understand it.

yes. thanks. um on the second question a would be -2 and b is 5. right?

Yup

a = -2, b = 5

y=2+3? That's just a horizontal line

is there suppose to be an x there somewhere haha

Yes, similarly

\[\frac{ f(5)-f(-2) }{ 5-(-2) }\]

making my answer for number 2 , --1? lol

Show your work

If it makes more sense, y = 3x+2 just means f(x) = 3x+2

You should not get -1

I got 3

That sounds good!

How did you get it

No, all these problems require calculus

You need to use \[\lim_{h \rightarrow 0} \frac{ f(a+h)-f(a) }{ h }\] use this definition to find it

It's not a linear equation it's y = -5x^2+2, if it was y = -5x+2 we could say slope is -5.

how would is et it up though?

\[\lim_{h \rightarrow 0} \frac{ f(1+h)-f(1) }{ h }\]

Can you do the rest?

im assuming h is 0? making my anser =cannot be determined?

Hey, why are they giving you these problems if you haven't learnt it yet..?

I don't know im in a pickle?. lol ok then is it -10?

Now simplify

-3? I put that previously a

Oh, I don't know.

Well since you're out of time I guess I will show you how to do it, the answer I got was -5. @magy33

|dw:1435652296303:dw|

Note that we keep the limit till we actually take the limit itself.