*Area of the base equals* a)8 pi square units b)16 pi square units c) 64 pi square units

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*Area of the base equals* a)8 pi square units b)16 pi square units c) 64 pi square units

Geometry
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I'm juggling one question back in forth.. so if I'm slow to reply sorry in advanced. Anyway we are given a cylinder |dw:1435669876398:dw|
It's okay
the formula for area of the base of a cylinder is A = pi(r^2)
Okay. But every time I put it into the calculator it shows: either 39.4384 or 50.24
I know.. we don't calculate the pi part.. leave it as is. so if r = 4 what is r^2?
looking at the choices... I think it doesn't want you to calculate the pi.. it's just finding the r and then squaring it
Well then it's just 16
So it's B?
A=pi(4^2) A=pi(16) =16 pi yeah
Thanks. So would it be about the same thing for this problem?
A cylinder has a volume of 245 pi cubic units and a height of 5 units. The diameter of the cylinder is a) 7 units b) 14 units c) 49 units
I think we need the diameter of the cylinder formula.
yeah we need a different formula for that.
\[\large V = \pi r^2h\]
so given height is 5 units volume is 245 pi cubic units . Looks like we're solve for r and then the diameter is twice the radius (d=2r) .. AHA! We need to find the radius first
Yes
ok let V = 245, and h = 5
V r h = � or 2 =
Well that didn't come out right
:(
\[\large 245 = \pi r^2(5)\]
What's "large"?
that's to make the font large
oh are you trying to use the equation tool? right click show math as -> tex command and it will have this code or text you can copy and paste. And then click on the equation tool and paste.
Oh
so we are solving for r that would mean that r needs to be by itself
our first goal is to have r^2 by itself .. and then afterwards we can take the square root
\[V = \pi r2h\]
r is squared
yeah it should have that ^ that carrot sign
\[\large V = \pi r^2h \]
anyway back to this \[\large 245 = \pi r^2(5) \] we need r^2 by itself so what do we need to do?
should we add both sides? subtract both sides? multiply both sides? or.. divide both sides by 5pi
divide both sides by 5 pi
yes. \[\large \frac{245}{5 \pi} = r^2\]
now we take the square root of both sides
So 49 = ?
Umm
we're not done.. we need to take the square root on both sides
UH OH! I need to refresh my screen is crazy
kk
Go ahead
I neded to digest a little
ok so taking the square root of both sides \[\large \sqrt{ \frac{245}{5 \pi} }= \sqrt{r^2}\] what is the square root of r^2
we need to take the square root of r^2 so we can have r
then once we have our r we can get the diameter. which is d =2r
r=2.5
that's not a choice for answers that would've yielded d = 5.. that's not right
No wait. 5 was the height not the diameter
mY BAD SRY
wait a minute we are solving for r.
we have already plugged in V and h... now we need to take the square root of both sides. We're almost there
I was thinking that the diameter is 7
cus 7 squared is 49
\[\large \sqrt{ \frac{245}{5 \pi} }= \sqrt{r^2} \] becomes ??? what is the square root of r^2
49 times 3.14 = 153.86
Umm
7
once we find r we can find the diameter which is d = 2r
What? ok no substituting we are solving for r we need the square root of r^2 .
I want an r by itself
we have square rooted both sides.. which is correct. Now we just need the square root of r^2 Then we have this \[\[\[\large \sqrt{ \frac{245}{5 \pi} }= r\] \]
now the diameter is d=2r so d = 2( That whole square root)
\[\large \sqrt{r^2} \rightarrow r^{\frac{2}{2}} \rightarrow r^1 \rightarrow r \]
so now our \[d=2(\sqrt{\frac{245}{5 \pi}})\]
so we just need 245 divided by 5 pi... take the square root of that result and multiply by 2
7.9
yes. so our diameter is 7.9 kind of a dangerous number because we can round up to 8
7 units would be the closest to the answer.. though the real answer is 7.9
Okay. Look I'm sorry if I aggravated you. It's been a long couple of weeks and I'm really tired
Thanks for the help. I really appreciate it
it's ok ... I'm also tired.. in fact it's almost 4 in the morning. I need zzz's before my dad get suspicious again.
that's why I had my latex wrong... r to the first power is just r if it was r^0 that would've been 1. But I should always take the advice of never do math while tired.
Yeah I can connect with that
I have to go sleep. night
Really. Wow it's 9:55 AM here
well alright
I live in Florida btw

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