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zarkam21

  • one year ago

Help, will medal

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  1. sloppycanada
    • one year ago
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    I see no question.

  2. anonymous
    • one year ago
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    Same, no question is here

  3. anonymous
    • one year ago
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    Tag me when your ready to give the question

  4. zarkam21
    • one year ago
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  5. zarkam21
    • one year ago
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    @LunaMizuki @sloppycanada

  6. sloppycanada
    • one year ago
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    Ohhh okay. So move everything on the right hand side of the = sign to the left side. Let me know what you get

  7. anonymous
    • one year ago
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  8. anonymous
    • one year ago
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    good luck :)

  9. zarkam21
    • one year ago
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  10. zarkam21
    • one year ago
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    That is what I got when I moved everything to the left side

  11. anonymous
    • one year ago
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    O.O dat handwriting tho lol

  12. sloppycanada
    • one year ago
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    Look closely. You added everything. You never truly moved it. |dw:1435672069964:dw|

  13. zarkam21
    • one year ago
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    Ohh okay so just move it the way it is into the equation on the left

  14. sloppycanada
    • one year ago
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    No no no no no. To move something algebraically the opposite must take place. So in our case -4x^2 must be added to both sides in order to "move it". Since the positive sign technically, for the moment, belongs to 3x, we can assume we must subtract 3x from both sides to move it. From the terribly drawn picture I drew, please simplify. You seem to have a few x^2s that could be fixed.

  15. anonymous
    • one year ago
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    then subtract 3x-4x^2 from both sides

  16. zarkam21
    • one year ago
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  17. zarkam21
    • one year ago
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    like that?

  18. sloppycanada
    • one year ago
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    Yup, almost there - You must have the 'x' go before the -5. |dw:1435672452778:dw|

  19. sloppycanada
    • one year ago
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    |dw:1435672475637:dw| Is the correct order.

  20. zarkam21
    • one year ago
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  21. zarkam21
    • one year ago
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    Okay

  22. zarkam21
    • one year ago
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    Is that the answer?

  23. sloppycanada
    • one year ago
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    Assuming you don't actually have to solve for "x" then, yes.

  24. zarkam21
    • one year ago
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    Thank you so much! =)

  25. sloppycanada
    • one year ago
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    Was I right?

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