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1 Attachment
Simplify. (x+3)^2
x^2+6?

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or 2x^2+6
You are squaring something 3^2 = ?
9
so 3^2=9
YUP!!!!! So your equation goes something along the lines of x^2 +/- x +/- # = 0 Fill in the blanks.
no its not
x^2-4x+9=0 ?
Simplify (x+3)2 + 4x Evaluate : (x+3)2 = x2+6x+9 Factoring x2+10x+9 (x+9) • (x+1) (x + 9) • (x + 1) = 0 Solve (x+9)•(x+1) = 0 Solve : x+9 = 0 Subtract 9 from both sides of the equation : x = -9 Solve : x+1 = 0 Subtract 1 from both sides of the equation : x = -1
No. you're not moving anything across an equal sign. so there's no need to change the postive and negative. x^2 + 4x + 9
@Albany_Goon The question isn't asking us to find "x". It's asking us to rearrange the equation.
ok so then its 0
because she has to write the cubic polynomial on the left hand side in standard form rite?
x^2-4x+9=0 ? is this correct?
@zarkam21 No, not quite. you seem to have the -4x wrong. It should be \[x^2+4x+9 = 0\]

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