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zarkam21

  • one year ago

Help pleasee

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  1. zarkam21
    • one year ago
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  2. sloppycanada
    • one year ago
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    Simplify. (x+3)^2

  3. zarkam21
    • one year ago
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    x^2+6?

  4. zarkam21
    • one year ago
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    or 2x^2+6

  5. sloppycanada
    • one year ago
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    You are squaring something 3^2 = ?

  6. zarkam21
    • one year ago
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    9

  7. zarkam21
    • one year ago
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    so 3^2=9

  8. sloppycanada
    • one year ago
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    YUP!!!!! So your equation goes something along the lines of x^2 +/- x +/- # = 0 Fill in the blanks.

  9. anonymous
    • one year ago
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    no its not

  10. zarkam21
    • one year ago
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    x^2-4x+9=0 ?

  11. anonymous
    • one year ago
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    Simplify (x+3)2 + 4x Evaluate : (x+3)2 = x2+6x+9 Factoring x2+10x+9 (x+9) • (x+1) (x + 9) • (x + 1) = 0 Solve (x+9)•(x+1) = 0 Solve : x+9 = 0 Subtract 9 from both sides of the equation : x = -9 Solve : x+1 = 0 Subtract 1 from both sides of the equation : x = -1

  12. sloppycanada
    • one year ago
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    No. you're not moving anything across an equal sign. so there's no need to change the postive and negative. x^2 + 4x + 9

  13. sloppycanada
    • one year ago
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    @Albany_Goon The question isn't asking us to find "x". It's asking us to rearrange the equation.

  14. anonymous
    • one year ago
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    ok so then its 0

  15. anonymous
    • one year ago
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    because she has to write the cubic polynomial on the left hand side in standard form rite?

  16. zarkam21
    • one year ago
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    x^2-4x+9=0 ? is this correct?

  17. sloppycanada
    • one year ago
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    @zarkam21 No, not quite. you seem to have the -4x wrong. It should be \[x^2+4x+9 = 0\]

  18. zarkam21
    • one year ago
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    Thanks @sloppycanada

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