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anonymous
 one year ago
The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more than the width, x, which interval can be the possible widths?
anonymous
 one year ago
The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more than the width, x, which interval can be the possible widths?

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sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0dw:1435674681668:dw Mae sense so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i still cant find answer

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.0This means we can assume the lengths of all four sides is equal to 172.

sloppycanada
 one year ago
Best ResponseYou've already chosen the best response.04x + 36 = 172 Simplify
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