A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more than the width, x, which interval can be the possible widths?

  • This Question is Closed
  1. sloppycanada
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1435674681668:dw| Mae sense so far?

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but i still cant find answer

  4. sloppycanada
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    This means we can assume the lengths of all four sides is equal to 172.

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  6. sloppycanada
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    4x + 36 = 172 Simplify

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.